Solve for x in the Parallelogram Area Equation: (x+3)(x-3)

The problem requires calculating the value of $x$ from the expression given for the area of a parallelogram: $(x+3)(x-3)$.

Recognize that the expression $(x+3)(x-3)$ can be expanded using the identity for the difference of squares:

$(x+3)(x-3) = x^2 - 3^2$

Thus, it simplifies to:

$x^2 - 9$

Understanding from the problem that this represents the area of the parallelogram, and after setting it equal to zero:

$x^2 - 9 = 0$

To solve for $x$, add 9 to both sides to isolate $x^2$:

$x^2 = 9$

Take the square root of both sides, remembering that squaring gives two solutions:

$x = \pm \sqrt{9} = \pm 3$

Thus, the solutions for $x$ are $x = 3$ and $x = -3$.

Therefore, the value of $x$ is $\pm6$.

Therefore, the solution to the problem is $x = \pm3$.