Solve for X: Understanding the Rectangle's Area via (4x+9)(4x-9)

Difference of Squares with Rectangle Area

The area of a rectangle is equal to (4x+9)(4x9) (4x+9)(4x-9) .

Calculate x.

777999

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find X
00:03 Use the formula for calculating rectangle area (side times side)
00:07 Substitute the side values according to the given data, and solve for the area
00:16 Substitute the area value according to the given data and solve for X
00:25 Use the shortened multiplication formulas to expand the brackets
00:41 Calculate 4 squared and 9 squared
00:46 Isolate X
01:19 Take the square root to find possible solutions for X
01:24 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

The area of a rectangle is equal to (4x+9)(4x9) (4x+9)(4x-9) .

Calculate x.

777999

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Simplify the expression (4x+9)(4x9)(4x+9)(4x-9) using the difference of squares formula.
  • Step 2: Calculate the area using the rectangle's given dimensions, 9 and 7.
  • Step 3: Equate the expressions and solve for xx.

Step 1: Simplifying (4x+9)(4x9)(4x+9)(4x-9).
This expression is a difference of squares, so it simplifies as follows:

(4x+9)(4x9)=(4x)292=16x281.(4x+9)(4x-9) = (4x)^2 - 9^2 = 16x^2 - 81.

Step 2: Calculate the area using given rectangle dimensions: 9 and 7.
The area AA of the rectangle is:

A=9×7=63.A = 9 \times 7 = 63.

Step 3: Equate the two expressions:
16x281=63.16x^2 - 81 = 63.
To solve for xx, start by adding 81 to both sides:

16x2=144.16x^2 = 144.

Divide both sides by 16 to isolate x2x^2:

x2=9.x^2 = 9.

Take the square root of both sides to solve for xx:

x=±9=±3.x = \pm\sqrt{9} = \pm3.

Therefore, the solution to the problem is x=±3 x = \pm3 .

3

Final Answer

±3 \operatorname{\pm}3

Key Points to Remember

Essential concepts to master this topic
  • Formula: Difference of squares: (a+b)(ab)=a2b2 (a+b)(a-b) = a^2 - b^2
  • Technique: (4x+9)(4x9)=16x281 (4x+9)(4x-9) = 16x^2 - 81 using the pattern
  • Check: Substitute x = 3: area = 16(9)81=63 16(9) - 81 = 63 matches 9×7 ✓

Common Mistakes

Avoid these frequent errors
  • Expanding (4x+9)(4x-9) using FOIL method
    Don't use FOIL to get 16x2+36x36x81 16x^2 + 36x - 36x - 81 = extra unnecessary work! This takes much longer and creates chances for arithmetic errors. Always recognize the difference of squares pattern and use (a+b)(ab)=a2b2 (a+b)(a-b) = a^2 - b^2 directly.

Practice Quiz

Test your knowledge with interactive questions

Solve:

\( (2+x)(2-x)=0 \)

FAQ

Everything you need to know about this question

How do I recognize when to use difference of squares?

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Look for the pattern (something + number)(same thing - same number). In this case, (4x+9)(4x9) (4x+9)(4x-9) has the same first term (4x) and the same second term (9) with opposite signs.

Why do we get both positive and negative answers?

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When we solve x2=9 x^2 = 9 , we take the square root of both sides. Since both 3² and (-3)² equal 9, we get two valid solutions: x = ±3.

How can a rectangle have a negative dimension?

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In pure geometry, lengths can't be negative. But in algebraic contexts like this problem, we accept both solutions because the mathematical relationship (4x+9)(4x9)=63 (4x+9)(4x-9) = 63 works for both x = 3 and x = -3.

What if I can't see the difference of squares pattern?

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Use FOIL as a backup! Expand (4x+9)(4x9) (4x+9)(4x-9) step by step: First + Outer + Inner + Last. You'll get 16x2+36x36x81 16x^2 + 36x - 36x - 81 , and notice the middle terms cancel out.

How do I check if x = -3 really works?

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Substitute back: (4(3)+9)(4(3)9)=(12+9)(129)=(3)(21)=63 (4(-3)+9)(4(-3)-9) = (-12+9)(-12-9) = (-3)(-21) = 63 . It matches the rectangle area of 9 × 7 = 63

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