Solve for X: Understanding the Rectangle's Area via (4x+9)(4x-9)

Question

The area of a rectangle is equal to (4x+9)(4x9) (4x+9)(4x-9) .

Calculate x.

777999

Video Solution

Solution Steps

00:00 Find X
00:03 Use the formula for calculating rectangle area (side times side)
00:07 Substitute the side values according to the given data, and solve for the area
00:16 Substitute the area value according to the given data and solve for X
00:25 Use the shortened multiplication formulas to expand the brackets
00:41 Calculate 4 squared and 9 squared
00:46 Isolate X
01:19 Take the square root to find possible solutions for X
01:24 And this is the solution to the question

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Simplify the expression (4x+9)(4x9)(4x+9)(4x-9) using the difference of squares formula.
  • Step 2: Calculate the area using the rectangle's given dimensions, 9 and 7.
  • Step 3: Equate the expressions and solve for xx.

Step 1: Simplifying (4x+9)(4x9)(4x+9)(4x-9).
This expression is a difference of squares, so it simplifies as follows:

(4x+9)(4x9)=(4x)292=16x281.(4x+9)(4x-9) = (4x)^2 - 9^2 = 16x^2 - 81.

Step 2: Calculate the area using given rectangle dimensions: 9 and 7.
The area AA of the rectangle is:

A=9×7=63.A = 9 \times 7 = 63.

Step 3: Equate the two expressions:
16x281=63.16x^2 - 81 = 63.
To solve for xx, start by adding 81 to both sides:

16x2=144.16x^2 = 144.

Divide both sides by 16 to isolate x2x^2:

x2=9.x^2 = 9.

Take the square root of both sides to solve for xx:

x=±9=±3.x = \pm\sqrt{9} = \pm3.

Therefore, the solution to the problem is x=±3 x = \pm3 .

Answer

±3 \operatorname{\pm}3