Solve log₅3 - log₅2: Working with Base-5 Logarithm Subtraction

log53log52= \log_53-\log_52=

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Step-by-step video solution

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00:00 Solve
00:04 We will use the formula for subtracting logarithms
00:13 Subtracting logarithms equals the logarithm of the quotient of numbers
00:19 We will use this formula in our exercise
00:34 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

log53log52= \log_53-\log_52=

2

Step-by-step solution

To solve the problem, we employ the property of logarithms for subtraction:

  • Step 1: Recognize the expression log53log52 \log_5 3 - \log_5 2 .
  • Step 2: Apply the logarithmic property for subtraction, logbalogbc=logb(ac) \log_b a - \log_b c = \log_b \left( \frac{a}{c} \right) .
  • Step 3: Substitute into the property: log53log52=log5(32) \log_5 3 - \log_5 2 = \log_5 \left( \frac{3}{2} \right) .

By applying the property, we simplify the expression to log532 \log_5 \frac{3}{2} . This is equivalent to log51.5 \log_5 1.5 . Therefore:

Therefore, the result of the expression is log51.5 \log_5 1.5 .

3

Final Answer

log51.5 \log_51.5

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\( \frac{1}{\log_49}= \)

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