Solve Complex Logarithm Expression: (1/2)log₂4 × log₃8 + log₃9 × log₃7

Logarithm Properties with Product Rules

12log24×log38+log39×log37= \frac{1}{2}\log_24\times\log_38+\log_39\times\log_37=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:10 Let's solve this problem together.
00:15 First, calculate the logarithm using its definition. Take your time.
00:23 Now, let's isolate the variable X. You're doing great, keep going!
00:27 Next, use the same method to calculate this logarithm. You've got this!
00:36 Here are the solutions for the logarithms. Nice work!
00:42 Now, substitute the values and keep solving. Let's see where it takes us.
00:53 Time to simplify what we can. Break it down step by step.
00:58 Use the power rule for logarithms. Move the two to the exponent. Keep it up!
01:12 Remember the formula for adding logarithms. Go ahead and use it.
01:23 Solve the exponent now. Almost there!
01:31 And that's how we find the solution to our question. Well done!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

12log24×log38+log39×log37= \frac{1}{2}\log_24\times\log_38+\log_39\times\log_37=

2

Step-by-step solution

We break it down into parts

log24=x \log_24=x

2x=4 2^x=4

x=2 x=2

log39=x \log_39=x

3x=9 3^x=9

x=2 x=2

We substitute into the equation

122log38+2log37= \frac{1}{2}\cdot2\log_38+2\log_37=

1log38+2log37= 1\cdot\log_38+2\log_37=

log38+log372= \log_38+\log_37^2=

log38+log349= \log_38+\log_349=

log3(849)=log3392 \log_3\left(8\cdot49\right)=\log_3392 x=2 x=2

3

Final Answer

log3392 \log_3392

Key Points to Remember

Essential concepts to master this topic
  • Rule: Simplify individual logarithms before combining them together
  • Technique: Use log24=2 \log_24 = 2 since 22=4 2^2 = 4
  • Check: Verify log3392 \log_3392 equals original expression by working backwards ✓

Common Mistakes

Avoid these frequent errors
  • Attempting to combine logarithms before simplifying
    Don't try to apply product rules to log24×log38 \log_24\times\log_38 directly = messy expressions! This ignores that log24=2 \log_24 = 2 and log39=2 \log_39 = 2 are simple integers. Always evaluate individual logarithms first.

Practice Quiz

Test your knowledge with interactive questions

\( \log_{10}3+\log_{10}4= \)

FAQ

Everything you need to know about this question

Why do we calculate log₂4 and log₃9 first?

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These are perfect power logarithms! Since 22=4 2^2 = 4 and 32=9 3^2 = 9 , both equal 2. This simplifies our expression dramatically before we apply other logarithm rules.

How do I know when to use the product rule for logarithms?

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Use loga(xy)=logax+logay \log_a(xy) = \log_ax + \log_ay when you see addition of logarithms with the same base. In this problem, we get log38+log349=log3(8×49) \log_38 + \log_349 = \log_3(8 \times 49) .

What does 2log₃7 become and why?

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Using the power rule, 2log37=log3(72)=log349 2\log_37 = \log_3(7^2) = \log_349 . The coefficient becomes an exponent inside the logarithm.

How do I multiply 8 × 49 quickly?

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Break it down: 8×49=8×(501)=4008=392 8 \times 49 = 8 \times (50-1) = 400 - 8 = 392 . Or use 8×72=8×49 8 \times 7^2 = 8 \times 49 .

Can I check my answer without a calculator?

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Yes! Work backwards: if the answer is log3392 \log_3392 , substitute back into the original expression step by step. Each part should simplify to give you confidence in your result.

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