Solve Nested Roots: Simplifying ¹⁰√(⁵√100) Step by Step

Nested Radicals with Index Multiplication

Solve the following exercise:

100510= \sqrt[10]{\sqrt[5]{100}}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve the following problem
00:03 When we have a number (A) to the power of (B) in a root of the order (C)
00:07 The result equals the number (A) in a root of order of their product (B times C)
00:11 We will apply this formula to our exercise
00:16 Calculate the order of the product
00:21 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following exercise:

100510= \sqrt[10]{\sqrt[5]{100}}=

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Use the formula for the nested radical: 100510=10010×5 \sqrt[10]{\sqrt[5]{100}} = \sqrt[10 \times 5]{100} .
  • Step 2: Calculate the product of the indices of the roots: 10×5=50 10 \times 5 = 50 .
  • Step 3: Write the simplified expression: 10050 \sqrt[50]{100} .

Let's apply these steps to find the solution:

First, we apply the root of a root property:
100510=10010×5 \sqrt[10]{\sqrt[5]{100}} = \sqrt[10 \times 5]{100}

This simplifies to:
10050 \sqrt[50]{100}

Therefore, the solution to the problem is 10050 \sqrt[50]{100} .

3

Final Answer

10050 \sqrt[50]{100}

Key Points to Remember

Essential concepts to master this topic
  • Rule: Root of a root multiplies indices together
  • Technique: 100510=10010×5=10050 \sqrt[10]{\sqrt[5]{100}} = \sqrt[10 \times 5]{100} = \sqrt[50]{100}
  • Check: Verify by working backwards: 10050=(10050)1/101/5 \sqrt[50]{100} = (\sqrt[50]{100})^{1/10 \cdot 1/5}

Common Mistakes

Avoid these frequent errors
  • Adding indices instead of multiplying
    Don't add 10 + 5 = 15 to get 10015 \sqrt[15]{100} = wrong answer! Adding indices doesn't follow the root property. Always multiply the indices: 10 × 5 = 50 for 10050 \sqrt[50]{100} .

Practice Quiz

Test your knowledge with interactive questions

Solve the following exercise:

\( \sqrt[5]{\sqrt[3]{5}}= \)

FAQ

Everything you need to know about this question

Why do we multiply the indices instead of adding them?

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When you have a root of a root, you're applying two operations in sequence. The mathematical property states anm=am×n \sqrt[m]{\sqrt[n]{a}} = \sqrt[m \times n]{a} . Think of it like exponents: (a1/n)1/m=a1/n×1/m=a1/(mn) (a^{1/n})^{1/m} = a^{1/n \times 1/m} = a^{1/(mn)} .

Can I simplify 10050 \sqrt[50]{100} further?

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Yes! Since 100=102 100 = 10^2 , you can write 10050=10250=102/50=101/25=1025 \sqrt[50]{100} = \sqrt[50]{10^2} = 10^{2/50} = 10^{1/25} = \sqrt[25]{10} . This is the most simplified form.

What if I have three nested roots like x543 \sqrt[3]{\sqrt[4]{\sqrt[5]{x}}} ?

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The same rule applies! Multiply all the indices: 3×4×5=60 3 \times 4 \times 5 = 60 , so the answer is x60 \sqrt[60]{x} . Work from inside out or multiply all at once.

How can I remember this rule?

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Think of roots as fractional exponents: 100510=(1001/5)1/10=1001/5×1/10=1001/50=10050 \sqrt[10]{\sqrt[5]{100}} = (100^{1/5})^{1/10} = 100^{1/5 \times 1/10} = 100^{1/50} = \sqrt[50]{100} . When you raise a power to another power, you multiply the exponents!

Does order matter in nested roots?

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No! 100510 \sqrt[10]{\sqrt[5]{100}} equals 100105 \sqrt[5]{\sqrt[10]{100}} because multiplication is commutative: 10×5=5×10=50 10 \times 5 = 5 \times 10 = 50 .

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