Solve the Nested Radical: Fourth Root of Square Root of 6

Solve the following exercise:

64= \sqrt[4]{\sqrt{6}}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve the following problem
00:03 A 'regular' root is of the order 2
00:09 When we have a number (A) to the power of (B) in a root of order (C)
00:14 The result equals the number (A) in a root of order of their product (B times C)
00:18 Let's apply this formula to our exercise
00:22 Calculate the order of the product
00:27 This is the solution

Step-by-step written solution

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1

Understand the problem

Solve the following exercise:

64= \sqrt[4]{\sqrt{6}}=

2

Step-by-step solution

To solve 64 \sqrt[4]{\sqrt{6}} , we'll simplify it using the property of roots:

According to the property xmn=xnm \sqrt[n]{\sqrt[m]{x}} = \sqrt[n \cdot m]{x} , we are to multiply the indices of the roots.

Here, the indices are 4 (for the fourth root) and 2 (for the square root), hence n=4 n = 4 and m=2 m = 2 .

Therefore, we calculate:

4×2=8 4 \times 2 = 8

This indicates that the expression can be rewritten as a single root of index 8, giving us:

64=68 \sqrt[4]{\sqrt{6}} = \sqrt[8]{6}

The answer is therefore 68 \sqrt[8]{6} , which matches answer choice 4.

3

Final Answer

68 \sqrt[8]{6}

Practice Quiz

Test your knowledge with interactive questions

Solve the following exercise:

\( \sqrt[5]{\sqrt[3]{5}}= \)

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