∣2x+1∣=9 \left| 2x + 1 \right| = 9 ∣2x+1∣=9
To solve ∣2x+1∣=9 \left| 2x + 1 \right| = 9 ∣2x+1∣=9, we consider two cases:
1. 2x+1=9 2x + 1 = 9 2x+1=9 implies 2x=8→x=4 2x = 8 \to x = 4 2x=8→x=4
2. 2x+1=−9 2x + 1 = -9 2x+1=−9 implies 2x=−10→x=−5 2x = -10 \to x = -5 2x=−10→x=−5
Thus, the solutions are x=4 x = 4 x=4 and x=−5 x = -5 x=−5.
x=4 x = 4 x=4, x=−5 x = -5 x=−5