Solve the Absolute Value Inequality: |x + 3| ≤ 5

To solve the inequality $|x + 3| \leq 5$, we first consider the definition of absolute value inequality $|A| \leq B$, which is equivalent to $-B \leq A \leq B$.

Applying this definition, we have:

$-5 \leq x + 3 \leq 5$

Next, we isolate x by subtracting 3 from all parts of the inequality:

$-5 - 3 \leq x + 3 - 3 \leq 5 - 3$

This simplifies to:

$-8 \leq x \leq 2$