If we have 65 blocks and we add a further 27 blocks, how many blocks will we have in total?
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If we have 65 blocks and we add a further 27 blocks, how many blocks will we have in total?
To solve this problem, we'll follow these steps:
Step 1: Align the numbers vertically by place value.
Step 2: Add the ones place digits and handle any carrying over if necessary.
Step 3: Add the tens place digits, including any carried over value.
Let's work through each step:
Step 1: Write the numbers 65 and 27 one below the other:
Step 2: Starting with the ones place, add 5 and 7 to get 12. Write down 2 and carry over 1 to the tens place.
Step 3: In the tens place, add 6 and 2, plus the carried over 1, giving a total of 9.
The calculation results in:
Therefore, the total number of blocks is .
If we have 67 blocks in total, how many blocks will remain if we remove 5 tens and 4 ones?
When adding digits gives you 10 or more, you write the ones digit and carry the tens digit to the next column left. Like when 5 + 7 = 12, write 2 and carry the 1!
Place value alignment is crucial! Ones must be under ones, tens under tens. If numbers aren't aligned properly, you'll add the wrong digits together and get incorrect results.
Always remember to add your carried digit to the next column! In this problem, 6 + 2 + 1 (carried) = 9. Forgetting the carried 1 would give you 8 instead of 9.
Use subtraction to check: 92 - 27 should equal 65, or 92 - 65 should equal 27. You can also add the numbers in reverse order: 27 + 65 = 92.
No! You only carry when the sum of digits in a column is 10 or greater. If 3 + 4 = 7, just write 7 - no carrying needed!
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