Solve the Algebraic Equation: 5 - (3b - 1) = 0

5(3b1)=0 5-(3b-1)=0

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Step-by-step video solution

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00:00 Solution
00:03 Open parentheses properly, multiply by each factor
00:17 Collect terms
00:24 Arrange the equation so that only the unknown B is on one side
00:34 Isolate B
00:40 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

5(3b1)=0 5-(3b-1)=0

2

Step-by-step solution

To solve the given linear equation 5(3b1)=0 5 - (3b - 1) = 0 , follow these steps:

  • Step 1: Simplify the equation.
    Start by distributing the negative sign through the parentheses:
    53b+1=0 5 - 3b + 1 = 0
  • Step 2: Combine like terms.
    Combine the constant terms on the left side:
    63b=0 6 - 3b = 0
  • Step 3: Isolate the variable b b .
    Subtract 6 from both sides of the equation to isolate the term with b b :
    3b=6-3b = -6
  • Step 4: Solve for b b .
    Divide both sides by -3 to solve for b b :
    b=63=2 b = \frac{-6}{-3} = 2

Therefore, the solution to the equation is b=2 b = 2 .

3

Final Answer

b=2 b=2

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\( 2(4-x)=8 \)

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