Solve the Algebraic Equation: 5 - (3b - 1) = 0

Linear Equations with Distribution and Simplification

5(3b1)=0 5-(3b-1)=0

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solution
00:03 Open parentheses properly, multiply by each factor
00:17 Collect terms
00:24 Arrange the equation so that only the unknown B is on one side
00:34 Isolate B
00:40 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

5(3b1)=0 5-(3b-1)=0

2

Step-by-step solution

To solve the given linear equation 5(3b1)=0 5 - (3b - 1) = 0 , follow these steps:

  • Step 1: Simplify the equation.
    Start by distributing the negative sign through the parentheses:
    53b+1=0 5 - 3b + 1 = 0
  • Step 2: Combine like terms.
    Combine the constant terms on the left side:
    63b=0 6 - 3b = 0
  • Step 3: Isolate the variable b b .
    Subtract 6 from both sides of the equation to isolate the term with b b :
    3b=6-3b = -6
  • Step 4: Solve for b b .
    Divide both sides by -3 to solve for b b :
    b=63=2 b = \frac{-6}{-3} = 2

Therefore, the solution to the equation is b=2 b = 2 .

3

Final Answer

b=2 b=2

Key Points to Remember

Essential concepts to master this topic
  • Distribution Rule: Apply negative sign to all terms inside parentheses
  • Technique: Combine like terms: 5 + 1 = 6 before isolating variable
  • Check: Substitute b = 2: 5 - (3(2) - 1) = 5 - 5 = 0 ✓

Common Mistakes

Avoid these frequent errors
  • Incorrectly distributing the negative sign
    Don't change 5 - (3b - 1) to 5 - 3b - 1 = wrong answer! This gives 4 - 3b = 0, so b = 4/3 instead of b = 2. Always distribute the negative to ALL terms: 5 - 3b + 1.

Practice Quiz

Test your knowledge with interactive questions

\( 5x=1 \)

What is the value of x?

FAQ

Everything you need to know about this question

Why does the -1 become +1 when I distribute?

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When you distribute a negative sign through parentheses, you multiply each term by -1. So -(-1) = +1. Think of it as: (3b1)=3b+1 -(3b - 1) = -3b + 1 .

What if I forget to combine like terms first?

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You'll make the problem harder! Always simplify first by combining constants (5 + 1 = 6) before trying to isolate the variable. This reduces mistakes.

Can I add 3b to both sides instead of subtracting 6?

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Yes! From 63b=0 6 - 3b = 0 , you can add 3b to get 6=3b 6 = 3b , then divide by 3. Both methods give b = 2.

How do I know when to distribute vs. when to divide?

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Look at the equation structure! When you see parentheses with a number or sign in front, distribute first. Only divide when you have a coefficient directly attached to your variable.

What does it mean when the equation equals zero?

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Setting an equation equal to zero means you're finding the root or solution where the expression has no value. This is very common in algebra!

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