Solving Equations Using the Distributive Property

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Solving an equation using the distributive property is related to the need to open the parentheses as the first step to then be able to simplify similar members. When an equation contains one or more pairs of parentheses, we must start by opening them all and then proceed to the next phase. 

Below, we provide you with some examples where this method is applied.

2(X+3)=8 2\left(X+3\right)=8

In this equation, we can clearly see some parentheses. To start, we must open them (that is, apply the distributive property) and then we can proceed with the following phases of the exercise.

2X+6=8 2X+6=8

2X=2 2X=2

X=1 X=1

The result of the equation is 1 1 .

Solving equations using the distributive property


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Another example

5(X+2)=3(X+4) 5\left(X+2\right)=3\left(X+4\right)

In this equation, we clearly see that there are two pairs of parentheses, one on each side. To begin, we must open them (that is, apply the distributive property) and then we can proceed with the following phases of the exercise.

5X+10=3X+12 5X+10=3X+12

2X=2 2X=2

X=1 X=1

The result of the equation is 1 1 .


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Examples and exercises with solutions for solving equations using the distributive property

Exercise #1

Solve x:

5(x+3)=0 5(x+3)=0

Video Solution

Step-by-Step Solution

We open the parentheses according to the formula:

a(x+b)=ax+ab a(x+b)=ax+ab

5×x+5×3=0 5\times x+5\times3=0

5x+15=0 5x+15=0

We will move the 15 to the right section and keep the corresponding sign:

5x=15 5x=-15

Divide both sections by 5

5x5=155 \frac{5x}{5}=\frac{-15}{5}

x=3 x=-3

Answer

3 -3

Exercise #2

Solve for x:

7(2x+5)=77 7(-2x+5)=77

Video Solution

Step-by-Step Solution

To open parentheses we will use the formula:

a(x+b)=ax+ab a(x+b)=ax+ab

(7×2x)+(7×5)=77 (7\times-2x)+(7\times5)=77

We multiply accordingly

14x+35=77 -14x+35=77

We will move the 35 to the right section and change the sign accordingly:

14x=7735 -14x=77-35

We solve the subtraction exercise on the right side and we will obtain:

14x=42 -14x=42

We divide both sections by -14

14x14=4214 \frac{-14x}{-14}=\frac{42}{-14}

x=3 x=-3

Answer

-3

Exercise #3

Solve for x:

2(4x)=8 2(4-x)=8

Video Solution

Step-by-Step Solution

To solve this equation, follow these steps:

  • Step 1: Apply the distributive property to the equation:

    2(4x)=2×42×x=82x 2(4-x) = 2 \times 4 - 2 \times x = 8 - 2x

  • Step 2: Simplify the equation:

    The equation now becomes: 82x=88 - 2x = 8

  • Step 3: Isolate the variable xx by simplifying the equation:

    First, subtract 8 from both sides:
    82x8=88 8 - 2x - 8 = 8 - 8
    This simplifies to:
    2x=0-2x = 0

  • Step 4: Solve for xx by dividing both sides by -2:

    x=02=0 x = \frac{0}{-2} = 0

Therefore, the solution to the equation is x=0x = 0.

Answer

0

Exercise #4

5(3b1)=0 5-(3b-1)=0

Video Solution

Step-by-Step Solution

To solve the given linear equation 5(3b1)=0 5 - (3b - 1) = 0 , follow these steps:

  • Step 1: Simplify the equation.
    Start by distributing the negative sign through the parentheses:
    53b+1=0 5 - 3b + 1 = 0
  • Step 2: Combine like terms.
    Combine the constant terms on the left side:
    63b=0 6 - 3b = 0
  • Step 3: Isolate the variable b b .
    Subtract 6 from both sides of the equation to isolate the term with b b :
    3b=6-3b = -6
  • Step 4: Solve for b b .
    Divide both sides by -3 to solve for b b :
    b=63=2 b = \frac{-6}{-3} = 2

Therefore, the solution to the equation is b=2 b = 2 .

Answer

b=2 b=2

Exercise #5

Determine the value of x x :

2(x+4)+8=0 2(x+4)+8=0

Video Solution

Step-by-Step Solution

Let's first expand the parentheses using the formula:

a(x+b)=ax+ab a(x+b)=ax+ab

(2×x)+(2×4)+8=0 (2\times x)+(2\times4)+8=0

2x+8+8=0 2x+8+8=0

Next, we will substitute in our terms accordingly:

2x+16=0 2x+16=0

Then, we will move the 16 to the left-hand side, keeping the appropriate sign:

2x=16 2x=-16

Finally, we divide both sides by 2:

2x2=162 \frac{2x}{2}=-\frac{16}{2}

x=8 x=-8

Answer

x=8 x=-8

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