Solve the Cubic Equation: 7x³-x² = 0 Using Factorization

Cubic Equations with Factoring by Common Terms

Solve the following problem:

7x3x2=0 7x^3-x^2=0

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find X
00:03 Factor with the X squared term
00:10 Take out the common factor from the parentheses
00:16 This is one solution that zeros the equation
00:21 Now let's check which solutions zero the second factor
00:25 Isolate X
00:30 And this is the solution to the problem

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following problem:

7x3x2=0 7x^3-x^2=0

2

Step-by-step solution

Solve the given equation:

7x3x2=0 7x^3-x^2=0

Note that on the left side we are able to factor the expression using a common factor. The largest common factor for the numbers and letters in this case is x2 x^2 since the second power is the lowest power in the equation and therefore is included both in the term with the third power and in the term with the second power. Any power higher than this is not included in the term with the second power, which is the lowest, and therefore this is the term with the highest power that can be factored out as a common factor from all terms in the expression.

7x3x2=0x2(7x1)=0 7x^3-x^2=0 \\ \downarrow\\ x^2(7x-1)=0

Note that the left side of the equation that we obtained in the last step is a multiplication of algebraic expressions and on the right side the number 0.

Therefore, given that the only way to obtain 0 from a multiplication operation is to multiply by 0. Hence at least one of the expressions in the multiplication on the left side must equal zero,

meaning:

x2=0/x=±0x=0 x^2=0 \hspace{8pt}\text{/}\sqrt{\hspace{6pt}}\\ x=\pm0\\ \boxed{x=0} (in this case taking the even root of the right side of the equation will indeed yield two possibilities, positive and negative. However since we're dealing with zero, we'll get only one possibility)

or:

7x1=0 7x-1=0 Let's solve this equation in order to obtain the additional solutions (if they exist) to the given equation:

We obtained a simple first-degree equation which we'll solve by isolating the unknown on one side, we'll do this by moving terms and then dividing both sides of the equation by the coefficient of the unknown:

7x1=07x=1/:7x=17 7x-1=0 \\ 7x=1\hspace{8pt}\text{/}:7\\ \boxed{x=\frac{1}{7}}

Let's summarize the solution of the equation:

7x3x2=0x2(7x1)=0x2=0x=07x1=0x=17x=0,17 7x^3-x^2=0 \\ \downarrow\\ x^2(7x-1)=0\\ \downarrow\\ x^2=0 \rightarrow\boxed{ x=0}\\ 7x-1=0\rightarrow \boxed{x=\frac{1}{7}}\\ \downarrow\\ \boxed{x=0,\frac{1}{7}}

Therefore the correct answer is answer C.

3

Final Answer

x=0,x=17 x=0,x=\frac{1}{7}

Key Points to Remember

Essential concepts to master this topic
  • Factor Rule: Find the highest common factor from all terms first
  • Technique: Factor out x2 x^2 from 7x3x2 7x^3-x^2 to get x2(7x1)=0 x^2(7x-1)=0
  • Check: Substitute both solutions: 7(0)3(0)2=0 7(0)^3-(0)^2=0 and 7(17)3(17)2=0 7(\frac{1}{7})^3-(\frac{1}{7})^2=0

Common Mistakes

Avoid these frequent errors
  • Forgetting the zero solution when factoring
    Don't ignore x2=0 x^2=0 after factoring = missing x=0 as a solution! Students often focus only on solving the linear factor and forget that the squared term also equals zero. Always set each factor equal to zero and solve both equations.

Practice Quiz

Test your knowledge with interactive questions

Solve the following equation:


\( 2x^2-8=x^2+4 \)

FAQ

Everything you need to know about this question

Why do we factor out x² instead of just x?

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We factor out the highest power that appears in ALL terms. Since we have 7x3 7x^3 and x2 x^2 , the highest common power is x2 x^2 . Factoring out x2 x^2 completely removes it from one term.

How do I know when a product equals zero?

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When a product of factors equals zero, at least one factor must be zero. So if x2(7x1)=0 x^2(7x-1)=0 , then either x2=0 x^2=0 OR 7x1=0 7x-1=0 (or both).

Why does x² = 0 give only one solution instead of two?

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While even roots usually give ± solutions, zero is special! Both +0 +0 and 0 -0 are the same number: 0. So x2=0 x^2=0 gives us only one unique solution: x=0.

What if I can't find a common factor?

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If there's no common factor, try other methods like grouping, substitution, or the rational root theorem. But always check for common factors first - it's the easiest method when it works!

Do I need to check both solutions in the original equation?

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Yes, always verify! Substitute both x=0 and x=17 x=\frac{1}{7} back into 7x3x2=0 7x^3-x^2=0 to confirm they both make the equation true.

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