Solve the Equation: x⁶ + x⁵ = 0 Using Common Factor Method

Polynomial Factoring with Common Factor Method

Solve the following problem:

x6+x5=0 x^6+x^5=0

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:07 Let's find the value of X.
00:10 First, factor the term with X raised to the fifth power.
00:18 Next, take out the common factor from inside the parentheses.
00:27 You've found one solution that makes the equation zero.
00:35 Now, let's check which values make the second factor equal zero.
00:40 Great job! And that's how we solve this problem.

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following problem:

x6+x5=0 x^6+x^5=0

2

Step-by-step solution

Shown below is the given equation:

x6+x5=0 x^6+x^5=0

First, note that on the left side we are able to factor the expression by using a common factor.

The largest common factor for the numbers and variables in this case is x5 x^5 given that the fifth power is the lowest power in the equation and therefore is included both in the term with the sixth power and in the term with the fifth power. Any power higher than this is not included in the term with the fifth power, which is the lowest, and therefore this is the term with the highest power that can be factored out as a common factor from all terms in the expression. Proceed with the factoring of the expression:

x6+x5=0x5(x+1)=0 x^6+x^5=0 \\ \downarrow\\ x^5(x+1)=0

Let's continue to the left side of the equation that we obtained in the last step. There is a multiplication of algebraic expressions and on the right side the number 0. Therefore, due to the fact that the only way to obtain 0 from a multiplication is to multiply by 0, at least one of the expressions in the multiplication on the left side must equal zero,

meaning:

x5=0/5x=0 x^5=0 \hspace{8pt}\text{/}\sqrt[5]{\hspace{6pt}}\\ \boxed{x=0} (in this case taking the odd root of the right side of the equation will yield one possibility)

or:

x+1=0x=1 x+1=0\\ \boxed{x=-1}

Let's summarize the solution of the equation:

x6+x5=0x5(x+1)=0x5=0x=0x+1=0x=1x=0,1 x^6+x^5=0 \\ \downarrow\\ x^5(x+1)=0 \\ \downarrow\\ x^5=0 \rightarrow\boxed{ x=0}\\ x+1=0 \rightarrow \boxed{x=-1}\\ \downarrow\\ \boxed{x=0,-1}

Therefore the correct answer is answer A.

3

Final Answer

x=1,x=0 x=-1,x=0

Key Points to Remember

Essential concepts to master this topic
  • Common Factor: Factor out highest power present in all terms
  • Technique: Factor x6+x5 x^6+x^5 as x5(x+1) x^5(x+1)
  • Check: Substitute x=0 and x=-1: both make original equation equal 0 ✓

Common Mistakes

Avoid these frequent errors
  • Factoring out wrong power of x
    Don't factor out x⁶ from both terms = impossible since x⁵ doesn't contain x⁶! This creates expressions that don't equal the original. Always factor out the lowest power that appears in all terms (x⁵ in this case).

Practice Quiz

Test your knowledge with interactive questions

Break down the expression into basic terms:

\( 2x^2 \)

FAQ

Everything you need to know about this question

Why do I factor out x⁵ instead of just x?

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You want the greatest common factor! While x divides both terms, x⁵ is the largest power that divides both x6 x^6 and x5 x^5 . This makes the factoring most efficient.

How do I know when a product equals zero?

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Use the Zero Product Property: if A×B=0 A \times B = 0 , then either A = 0 or B = 0 (or both). So x5(x+1)=0 x^5(x+1) = 0 means x5=0 x^5 = 0 or x+1=0 x+1 = 0 .

Why does x⁵ = 0 give only x = 0?

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When you have x5=0 x^5 = 0 , taking the fifth root of both sides gives x = 0. Unlike even roots, odd roots always give exactly one solution.

Do I need to check my answers?

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Always verify! Substitute each solution back: 06+05=0 0^6 + 0^5 = 0 ✓ and (1)6+(1)5=1+(1)=0 (-1)^6 + (-1)^5 = 1 + (-1) = 0

What if I can't see the common factor right away?

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List the factors of each term separately! For x6+x5 x^6 + x^5 : the first term has factors x⁶, x⁵, x⁴... and the second has x⁵, x⁴, x³... The largest common one is x⁵.

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