Solve the Equation: 1/4y + 1/2y + 5 - 12 = 0

$\frac{1}{4}y+\frac{1}{2}y+5-12=0$

$y=\text{?}$

To solve the given linear equation, we will follow these steps:

• Step 1: Combine the terms involving $y$.
• Step 2: Simplify the constants on the right side of the equation.
• Step 3: Isolate $y$ to find its value.

Let’s solve the equation $\frac{1}{4}y + \frac{1}{2}y + 5 - 12 = 0$.

Step 1: Combine the like terms that involve $y$.
The coefficients of $y$ are $\frac{1}{4}$ and $\frac{1}{2}$. To combine them, we need a common denominator, which is 4. Therefore:

$\frac{1}{4}y + \frac{1}{2}y = \frac{1}{4}y + \frac{2}{4}y = \frac{3}{4}y$.

Step 2: Simplify the constants.
The equation now becomes $\frac{3}{4}y + 5 - 12 = 0$.
Combine the constants: $5 - 12 = -7$.

The equation simplifies to $\frac{3}{4}y - 7 = 0$.

Step 3: Isolate $y$.
Add 7 to both sides of the equation:
$\frac{3}{4}y = 7$.

To solve for $y$, multiply both sides by the reciprocal of $\frac{3}{4}$, which is $\frac{4}{3}$:

$y = 7 \times \frac{4}{3} = \frac{28}{3}$.

Convert the fraction to a mixed number: $\frac{28}{3} = 9 \cdot 3 + 1 = 9 \text{ remainder } 1$. Thus, $\frac{28}{3} = 9\frac{1}{3}$.

Therefore, the value of $y$ is $9\frac{1}{3}$.