Solve the Equation: 3y(?-?) = 21xy + 9 | Finding Missing Terms

Fill in the missing values:

3y(??)=21xy+9 3y(?-?)=21xy+9

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Complete the missing values
00:04 Factorize 21 into factors 3 and 7
00:10 Factorize 9 into factors 3 and 3
00:15 Multiply by the appropriate whole fraction
00:30 Mark the common factors
00:43 Take out the common factors from the parentheses
00:50 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Fill in the missing values:

3y(??)=21xy+9 3y(?-?)=21xy+9

2

Step-by-step solution

To solve the problem, follow these steps:

  • Step 1: Recognize the expression 21xy+9 21xy + 9 needs to be matched by factoring it as a common product expression that includes 3y 3y .
  • Step 2: Identify the greatest common factor in 21xy+9 21xy + 9 , which is 3 3 . Thus, the factorization is 3(7xy+3) 3(7xy + 3) .
  • Step 3: Now, we need 3y(??)=3(7xy+3) 3y(?-?) = 3(7xy + 3) . Since we factor out a 3 3 , the matching terms should sum up to y(7x)+y(3y) y(7x) + y\left(\frac{-3}{y}\right) .
  • Step 4: Match the missing numbers found in the expression: ??=7x,3y ? - ? = 7x, \frac{-3}{y} .

By matching, the factors yield 3y(??)=3y(7x3y) 3y(?-?) = 3y(7x - \frac{3}{y}) . This confirms the missing values are 7x 7x and 3y \frac{-3}{y} .

Therefore, the correct completion of the expression is 7x,3y 7x, \frac{-3}{y} , which corresponds to choice 4.

3

Final Answer

7x,3y 7x,\frac{-3}{y}

Practice Quiz

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Break down the expression into basic terms:

\( 4x^2 + 6x \)

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