Solve the Equation: Finding the Unknown Factor in ?(b+8) = a+8a/b

Algebraic Factoring with Mixed Expressions

Fill in the missing value:

?(b+8)=a+8ab ?(b+8)=a+8\frac{a}{b}

❤️ Continue Your Math Journey!

We have hundreds of course questions with personalized recommendations + Account 100% premium

Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Complete the missing values
00:05 Multiply by the appropriate whole fraction
00:19 Use the commutative property
00:23 Mark the common factors
00:31 Take out the common factors from the parentheses
00:35 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Fill in the missing value:

?(b+8)=a+8ab ?(b+8)=a+8\frac{a}{b}

2

Step-by-step solution

To solve this problem, we'll fill in the missing value in the equation:

?(b+8)=a+8ab ?(b+8)=a+8\frac{a}{b}

Let's follow these steps:

  • Step 1: Let's represent the missing value as x x . Thus, the equation becomes x(b+8)=a+8ab x(b + 8) = a + 8\frac{a}{b} .
  • Step 2: Distribute x x on the left-hand side: xb+8x=a+8ab xb + 8x = a + 8\frac{a}{b} .
  • Step 3: To equate both sides of the equation, observe that the expression on the right can be decomposed as a+8ab a + 8\frac{a}{b} .
  • Step 4: By factoring a a in the right-hand side expression: a+8ab=a(1+8b) a + \frac{8a}{b} = a\left(1 + \frac{8}{b}\right) .
  • Step 5: For the expressions xb+8x xb + 8x and a(1+8b) a\left(1 + \frac{8}{b}\right) to be equal, the factor x x must be equal to the common factor applied to b+8 b + 8 and the factored right-hand side.
  • Step 6: Set each coefficient or common factor equal: x=ab x = \frac{a}{b} .

Therefore, the missing value in the equation is ab\frac{a}{b}.

3

Final Answer

ab \frac{a}{b}

Key Points to Remember

Essential concepts to master this topic
  • Pattern Recognition: Factor out common variables from mixed fraction expressions
  • Technique: Factor a+8ab=a(1+8b) a + 8\frac{a}{b} = a(1 + \frac{8}{b}) to match left side
  • Check: Substitute ab(b+8)=a+8ab \frac{a}{b}(b+8) = a + 8\frac{a}{b}

Common Mistakes

Avoid these frequent errors
  • Trying to solve by expanding instead of factoring
    Don't expand the left side and create complex algebra = messy calculations with multiple variables! This leads to confusion and wrong answers. Always look for factoring patterns first to simplify both sides.

Practice Quiz

Test your knowledge with interactive questions

Break down the expression into basic terms:

\( 4x^2 + 6x \)

FAQ

Everything you need to know about this question

How do I know what to factor out from the right side?

+

Look for the common variable in both terms! In a+8ab a + 8\frac{a}{b} , both terms contain 'a', so factor out a to get a(1+8b) a(1 + \frac{8}{b}) .

Why does factoring help me find the missing value?

+

Factoring reveals the structure of the equation! When you factor the right side as a(1+8b) a(1 + \frac{8}{b}) , you can see it matches the pattern something times (b+8) on the left.

What if I can't see the factoring pattern right away?

+

Start by identifying common factors in each term. Write out what you see: both terms on the right have 'a', so pull it out front. Practice makes pattern recognition easier!

How do I verify my answer is correct?

+

Substitute your answer back! Replace the ? with ab \frac{a}{b} : ab(b+8)=a+8ab \frac{a}{b}(b+8) = a + 8\frac{a}{b} . Expand the left side to check both sides match.

Can I solve this without factoring?

+

While possible, factoring is the most efficient method. Other approaches like expanding create more complex algebra. Factoring shows the relationship clearly and leads to the answer faster.

🌟 Unlock Your Math Potential

Get unlimited access to all 18 Algebraic Technique questions, detailed video solutions, and personalized progress tracking.

📹

Unlimited Video Solutions

Step-by-step explanations for every problem

📊

Progress Analytics

Track your mastery across all topics

🚫

Ad-Free Learning

Focus on math without distractions

No credit card required • Cancel anytime

More Questions

Click on any question to see the complete solution with step-by-step explanations