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Let's solve the equation. First, we'll simplify the algebraic expressions using the perfect square binomial formula:
We'll apply the mentioned formula and expand the parentheses in the expressions in the equation:
We'll continue and combine like terms, by moving terms between sides. Later - we can notice that the squared term cancels out, therefore it's a first-degree equation, which we'll solve by isolating the variable term on one side and dividing both sides of the equation by its coefficient:
Therefore, the correct answer is answer A.
Choose the expression that has the same value as the following:
\(  (x+3)^2  \)
After expanding (x+1)² to x² + 2x + 1, you have x² on both sides of the equation. When you subtract x² from both sides, they cancel out, leaving just 2x + 1 = 0.
Think FOIL: (x+1)(x+1) = x² + x + x + 1 = x² + 2x + 1. The middle term is always twice the product of the two terms inside the parentheses.
Double-check your algebra! The correct expansion gives 2x + 1 = 0, so 2x = -1, making x = -1/2 (negative). A positive answer means an error in signs.
Not really! You need to see what's inside the parentheses. Taking square roots would give |x+1| = |x|, which creates a more complex absolute value equation.
Even though we start with x² terms, they cancel out during solving! This leaves us with just 2x + 1 = 0, which is linear (first-degree).
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