Solve the Equation: x² + 9 = 0 Step-by-Step

Quadratic Equations with Complex Solutions

x2+9=0 x^2+9=0

Solve the equation

❤️ Continue Your Math Journey!

We have hundreds of course questions with personalized recommendations + Account 100% premium

Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find X
00:03 Isolate X
00:08 Every number squared is greater than 0
00:14 Minus 9 is negative, therefore there is no solution
00:18 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

x2+9=0 x^2+9=0

Solve the equation

2

Step-by-step solution

The parameters are expressed in the quadratic equation as follows:

aX2+bX+c=0

We identify that we have:
a=1
b=0
c=9

We recall the root formula:

Roots formula | The version

We replace according to the formula:

-0 ± √(0²-4*1*9)

2

We will focus on the part inside the square root (also called delta)

√(0-4*1*9)

√(0-36)

√-36

It is not possible to take the square root of a negative number.

And so the question has no solution.

3

Final Answer

No solution

Key Points to Remember

Essential concepts to master this topic
  • Discriminant Rule: When b24ac<0 b^2 - 4ac < 0 , equation has no real solutions
  • Technique: Calculate discriminant: 024(1)(9)=36 0^2 - 4(1)(9) = -36 (negative)
  • Check: Negative discriminant means 36 \sqrt{-36} is undefined in real numbers ✓

Common Mistakes

Avoid these frequent errors
  • Attempting to solve by isolating x²
    Don't subtract 9 from both sides to get x2=9 x^2 = -9 then take the square root = x=±3 x = ±3 ! This ignores that square roots of negative numbers don't exist in real numbers. Always check if the discriminant is negative before attempting to find real solutions.

Practice Quiz

Test your knowledge with interactive questions

a = Coefficient of x²

b = Coefficient of x

c = Coefficient of the independent number


what is the value of \( a \) in the equation

\( y=3x-10+5x^2 \)

FAQ

Everything you need to know about this question

Why can't I just say x = ±3 when x² = -9?

+

Because no real number squared gives a negative result. When you square any real number (positive or negative), you always get a positive result or zero. Since 32=9 3^2 = 9 and (3)2=9 (-3)^2 = 9 , neither equals -9.

What does 'no solution' actually mean?

+

It means there are no real numbers that satisfy the equation. The equation has no solutions in the real number system we typically work with in algebra.

How do I know when to use the discriminant?

+

Always calculate the discriminant b24ac b^2 - 4ac for quadratic equations. If it's negative, you have no real solutions. If it's zero, you have one solution. If it's positive, you have two solutions.

Are there any solutions at all?

+

In advanced mathematics, there are complex solutions involving imaginary numbers (x=±3i x = ±3i ), but in basic algebra, we say 'no solution' when referring to real numbers only.

Could I have made a calculation error?

+

Always double-check! Verify a=1 a = 1 , b=0 b = 0 , c=9 c = 9 , then calculate 024(1)(9)=36 0^2 - 4(1)(9) = -36 . Since this is negative, 'no solution' is correct.

🌟 Unlock Your Math Potential

Get unlimited access to all 18 Solving Quadratic Equations questions, detailed video solutions, and personalized progress tracking.

📹

Unlimited Video Solutions

Step-by-step explanations for every problem

📊

Progress Analytics

Track your mastery across all topics

🚫

Ad-Free Learning

Focus on math without distractions

No credit card required • Cancel anytime

More Questions

Click on any question to see the complete solution with step-by-step explanations