Solve the Nested Root Expression: Fifth Root of Cube Root of 5

Nested Radical Expressions with Exponent Rules

Solve the following exercise:

535= \sqrt[5]{\sqrt[3]{5}}=

❤️ Continue Your Math Journey!

We have hundreds of course questions with personalized recommendations + Account 100% premium

Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve the following problem
00:04 When we have a number (A) in a root of the order (B) in a root of the order (C)
00:09 The result equals the number (A) in a root of the order of their product (B times C)
00:13 Let's apply this formula to our exercise
00:19 Calculate the order of multiplication
00:24 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following exercise:

535= \sqrt[5]{\sqrt[3]{5}}=

2

Step-by-step solution

To solve the problem of finding 535 \sqrt[5]{\sqrt[3]{5}} , we'll use the formula for a root of a root, which combines the exponents:

  • Step 1: Express each root as an exponent.
    We start with the innermost root: 53=51/3 \sqrt[3]{5} = 5^{1/3} .
  • Step 2: Apply the outer root.
    The square root to the fifth power is expressed as: 51/35=(51/3)1/5 \sqrt[5]{5^{1/3}} = (5^{1/3})^{1/5} .
  • Step 3: Combine the exponents.
    Using the exponent rule (am)n=am×n(a^m)^n = a^{m \times n}, we get:
    (51/3)1/5=5(1/3)×(1/5)=51/15(5^{1/3})^{1/5} = 5^{(1/3) \times (1/5)} = 5^{1/15}.
  • Step 4: Convert the exponent back to root form.
    This can be written as 515 \sqrt[15]{5} .

Therefore, the simplified expression of 535 \sqrt[5]{\sqrt[3]{5}} is 515 \sqrt[15]{5} .

3

Final Answer

515 \sqrt[15]{5}

Key Points to Remember

Essential concepts to master this topic
  • Exponent Rule: Convert nested roots to fractional exponents first
  • Technique: Multiply exponents: (51/3)1/5=51/3×1/5=51/15 (5^{1/3})^{1/5} = 5^{1/3 \times 1/5} = 5^{1/15}
  • Check: Verify by working backwards: (515)15=5 (\sqrt[15]{5})^{15} = 5

Common Mistakes

Avoid these frequent errors
  • Adding the root indices instead of multiplying exponents
    Don't add 5 + 3 = 8 to get 58 \sqrt[8]{5} ! This ignores the nested structure and gives a completely wrong answer. Always convert to fractional exponents first, then multiply: 1/3 × 1/5 = 1/15.

Practice Quiz

Test your knowledge with interactive questions

Solve the following exercise:

\( \sqrt[10]{\sqrt[10]{1}}= \)

FAQ

Everything you need to know about this question

Why do I convert roots to fractional exponents?

+

Converting to fractional exponents makes it much easier to apply exponent rules! an=a1/n \sqrt[n]{a} = a^{1/n} transforms the problem into simple multiplication of fractions.

How do I multiply fractions like 1/3 × 1/5?

+

Multiply the numerators together and the denominators together: 13×15=1×13×5=115 \frac{1}{3} \times \frac{1}{5} = \frac{1 \times 1}{3 \times 5} = \frac{1}{15}

Can I work from the outside root inward instead?

+

Yes, but it's more confusing! Starting with the innermost root 53 \sqrt[3]{5} and working outward follows the natural order of operations and is less error-prone.

What if there were three nested roots?

+

Same process! Convert each root to a fractional exponent and multiply all the fractions. For example: 5432=51/4×1/3×1/2=51/24 \sqrt[2]{\sqrt[3]{\sqrt[4]{5}}} = 5^{1/4 \times 1/3 \times 1/2} = 5^{1/24}

How can I check if my final answer is correct?

+

Work backwards! If your answer is 515 \sqrt[15]{5} , then (515)15 (\sqrt[15]{5})^{15} should equal 5. You can also use a calculator to verify both expressions give the same decimal value.

🌟 Unlock Your Math Potential

Get unlimited access to all 18 Rules of Roots questions, detailed video solutions, and personalized progress tracking.

📹

Unlimited Video Solutions

Step-by-step explanations for every problem

📊

Progress Analytics

Track your mastery across all topics

🚫

Ad-Free Learning

Focus on math without distractions

No credit card required • Cancel anytime

More Questions

Click on any question to see the complete solution with step-by-step explanations