Solve the Quadratic Equation: 9y² - 30y = -25

9y230y=25 9y^2-30y=-25

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Step-by-step video solution

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00:00 Find Y
00:03 Arrange the equation so one side equals 0
00:16 Factor 3Y squared
00:19 Factor 25 to 5 squared
00:24 Factor 30 into 2, 3 and 5
00:35 Use the quadratic formulas to find the binomial
00:38 Take the square root to eliminate the square
00:42 Isolate Y
00:49 And this is the solution to the problem

Step-by-step written solution

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1

Understand the problem

9y230y=25 9y^2-30y=-25

2

Step-by-step solution

To solve the quadratic equation 9y230y=259y^2 - 30y = -25, we first rewrite it in standard form:

9y230y+25=09y^2 - 30y + 25 = 0.

Identifying the coefficients, we have a=9a = 9, b=30b = -30, and c=25c = 25. We will apply the quadratic formula:

y=b±b24ac2a y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} .

First, compute the discriminant:

b24ac=(30)24925=900900=0b^2 - 4ac = (-30)^2 - 4 \cdot 9 \cdot 25 = 900 - 900 = 0.

Since the discriminant is zero, there is a single repeated root. Substituting back into the quadratic formula, we get:

y=(30)±029=3018=53 y = \frac{-(-30) \pm \sqrt{0}}{2 \cdot 9} = \frac{30}{18} = \frac{5}{3} .

Therefore, the solution to the equation is y=53 y = \frac{5}{3} .

3

Final Answer

y=53 y=\frac{5}{3}

Practice Quiz

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Solve the following equation:

\( 2x^2-10x-12=0 \)

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