9y2−30y=−25
To solve the quadratic equation 9y2−30y=−25, we first rewrite it in standard form:
9y2−30y+25=0.
Identifying the coefficients, we have a=9, b=−30, and c=25. We will apply the quadratic formula:
y=2a−b±b2−4ac.
First, compute the discriminant:
b2−4ac=(−30)2−4⋅9⋅25=900−900=0.
Since the discriminant is zero, there is a single repeated root. Substituting back into the quadratic formula, we get:
y=2⋅9−(−30)±0=1830=35.
Therefore, the solution to the equation is y=35.