Solve the Quadratic Equation: 9y² - 30y = -25

Quadratic Formula with Zero Discriminant

9y230y=25 9y^2-30y=-25

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:07 Let's find Y. Ready?
00:10 First, make sure one side of the equation equals zero. This sets the stage for solving it.
00:23 Now, let's factor 3, Y squared. We break it down step-by-step.
00:28 Next, think of 25 as 5 squared. This helps us later.
00:33 Now, factor 30 into two, three, and five. Great job so far!
00:42 We can use the quadratic formula to find our binomial expression. Keep going!
00:47 Next, we take the square root to remove the square. Almost there!
00:52 Now, isolate Y. You're doing great!
00:56 And there you have it! That's the solution to our problem.

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

9y230y=25 9y^2-30y=-25

2

Step-by-step solution

To solve the quadratic equation 9y230y=259y^2 - 30y = -25, we first rewrite it in standard form:

9y230y+25=09y^2 - 30y + 25 = 0.

Identifying the coefficients, we have a=9a = 9, b=30b = -30, and c=25c = 25. We will apply the quadratic formula:

y=b±b24ac2a y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} .

First, compute the discriminant:

b24ac=(30)24925=900900=0b^2 - 4ac = (-30)^2 - 4 \cdot 9 \cdot 25 = 900 - 900 = 0.

Since the discriminant is zero, there is a single repeated root. Substituting back into the quadratic formula, we get:

y=(30)±029=3018=53 y = \frac{-(-30) \pm \sqrt{0}}{2 \cdot 9} = \frac{30}{18} = \frac{5}{3} .

Therefore, the solution to the equation is y=53 y = \frac{5}{3} .

3

Final Answer

y=53 y=\frac{5}{3}

Key Points to Remember

Essential concepts to master this topic
  • Standard Form: Move all terms to one side first
  • Discriminant: Calculate b24ac=900900=0 b^2 - 4ac = 900 - 900 = 0
  • Check: Substitute y=53 y = \frac{5}{3} back into original equation ✓

Common Mistakes

Avoid these frequent errors
  • Forgetting to rearrange equation to standard form first
    Don't apply the quadratic formula to 9y230y=25 9y^2 - 30y = -25 directly = wrong coefficients! This gives incorrect values for a, b, and c, leading to completely wrong answers. Always rearrange to ay2+by+c=0 ay^2 + by + c = 0 form first.

Practice Quiz

Test your knowledge with interactive questions

a = Coefficient of x²

b = Coefficient of x

c = Coefficient of the independent number


what is the value of \( a \) in the equation

\( y=3x-10+5x^2 \)

FAQ

Everything you need to know about this question

What does it mean when the discriminant equals zero?

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When b24ac=0 b^2 - 4ac = 0 , there's exactly one solution (a repeated root). The parabola touches the x-axis at only one point instead of crossing it twice.

Do I always need to use the quadratic formula?

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Not always! This equation could also be solved by factoring since 9y230y+25=(3y5)2 9y^2 - 30y + 25 = (3y - 5)^2 . Try factoring first - if it doesn't work easily, use the formula.

How do I know which method to choose?

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Look for perfect square trinomials first (like this problem). If the discriminant is a perfect square, factoring might be easier. Otherwise, the quadratic formula always works!

Why did we get a fraction as the answer?

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Fractions are common solutions! Since we have y=3018 y = \frac{30}{18} , always simplify by dividing both numerator and denominator by their GCD (6) to get 53 \frac{5}{3} .

How can I check if my answer is correct?

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Substitute y=53 y = \frac{5}{3} into the original equation: 9(53)230(53)=9(259)50=2550=25 9(\frac{5}{3})^2 - 30(\frac{5}{3}) = 9(\frac{25}{9}) - 50 = 25 - 50 = -25

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