Solve the Quadratic Equation: ax² + 5a + x = (3 + a)x² - (x + a)²

Quadratic Equations with Parameter Constraints

Solve the following equation:

ax2+5a+x=(3+a)x2(x+a)2 ax^2+5a+x=(3+a)x^2-(x+a)^2

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:10 Let's start by finding where A is defined.
00:20 Next, open brackets using multiplication rules.
00:40 Arrange the equation so the right side equals zero.
00:50 Factor out any common terms in the parentheses.
01:21 Simplify further by opening the brackets.
01:37 Use the root part of the quadratic formula.
01:42 Make sure this is zero or positive, no negative root allowed .
01:47 Now, check the coefficients with respect to X.
01:59 Plug in values and solve.
02:09 Again, open brackets using multiplication rules.
02:24 Multiply and distribute each factor.
02:36 Combine like terms together.
02:47 Treat it as an equation, instead of inequality.
02:52 Once more, examine coefficients and proceed.
02:57 Apply the quadratic formula.
03:09 Substitute appropriate values to find solutions.
03:24 Compute squares and multiplications needed.
03:47 Here are the two possible solutions for A.
04:02 Revisit the inequality and determine A's domain.
04:16 The parabola curves upwards, so it's positive.
04:21 Identify where the graph is zero or positive.
04:30 And that's how to solve this problem!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following equation:

ax2+5a+x=(3+a)x2(x+a)2 ax^2+5a+x=(3+a)x^2-(x+a)^2

2

Step-by-step solution

To solve the given equation ax2+5a+x=(3+a)x2(x+a)2 ax^2 + 5a + x = (3+a)x^2 - (x+a)^2 , we begin with expansion and simplification:

  • Step 1: Expand the terms on the right side:
    (3+a)x2(x+a)2=(3+a)x2(x2+2ax+a2)=(3+a)x2x22axa2(3+a)x^2 - (x+a)^2 = (3+a)x^2 - (x^2 + 2ax + a^2) = (3+a)x^2 - x^2 - 2ax - a^2
  • Step 2: Simplify further:
    (3+a)x2x22axa2=2ax22axa2+3x2 (3+a)x^2 - x^2 - 2ax - a^2 = 2ax^2 - 2ax - a^2 + 3x^2
  • Step 3: Collect and equate coefficients from both sides:
    0=(2a+2aa)x2+(a5)xa2 0 = (2a + 2a - a)x^2 + (a - 5)x - a^2
  • Step 4: Set each type of coefficient separately to zero, assuming that the equation is valid for all x x :
    - Coefficient of x2 x^2 : a=3 a = 3
    - Coefficient of x x : 1=2a1 1 = 2a - 1
    Solving these inequalities in terms of a a gives us the final inequality solution.

From the analysis, the solution is constrained by the inequalities derived from the simplification process. Hence, the answer is:
Thus, the solution to the problem is 3.644a,0.023a -3.644 \ge a, -0.023 \le a .

3

Final Answer

3.644a,0.023a -3.644\ge a,-0.023\le a

Key Points to Remember

Essential concepts to master this topic
  • Expansion Rule: Expand all squared terms and distribute coefficients completely
  • Technique: Collect like terms: ax2+5a+x=(2+a)x22axa2 ax^2 + 5a + x = (2+a)x^2 - 2ax - a^2
  • Check: Rearrange to standard form and analyze coefficient constraints ✓

Common Mistakes

Avoid these frequent errors
  • Incorrectly expanding squared binomials
    Don't expand (x+a)2 (x+a)^2 as just x2+a2 x^2 + a^2 = missing the middle term! This drops the crucial 2ax 2ax term and changes the entire equation. Always remember (x+a)2=x2+2ax+a2 (x+a)^2 = x^2 + 2ax + a^2 using FOIL or the perfect square formula.

Practice Quiz

Test your knowledge with interactive questions

a = coefficient of x²

b = coefficient of x

c = coefficient of the constant term


What is the value of \( c \) in the function \( y=-x^2+25x \)?

FAQ

Everything you need to know about this question

Why does this problem give me ranges for 'a' instead of specific values?

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This equation involves a parameter 'a' that affects the coefficients. The solution shows which values of 'a' make the equation valid, creating inequality constraints rather than exact solutions.

How do I expand (x+a)2 (x+a)^2 correctly?

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Use the formula (x+a)2=x2+2ax+a2 (x+a)^2 = x^2 + 2ax + a^2 . Remember the middle term 2ax 2ax - it's the most commonly forgotten part!

What does it mean when coefficients must equal zero?

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When rearranging gives 0=Ax2+Bx+C 0 = Ax^2 + Bx + C , this equation must hold for all values of x. This means each coefficient (A, B, C) must individually equal zero.

Why are there two separate inequality conditions in the answer?

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The parameter 'a' must satisfy both constraints simultaneously. The format a3.644 a \ge -3.644 OR a0.023 a \le -0.023 shows two separate valid ranges for the parameter.

How do I check if my expansion is correct?

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Pick a simple value like a = 1, x = 2 and substitute into both the original equation and your expanded form. If both sides give the same result, your expansion is correct!

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