Solve the Quadratic Equation: x² - 3x + 2 = 0

Question

Solve the following equation:

$x^2-3x+2=0$

00:00 Find X

00:03 Use the roots formula

00:23 Identify the coefficients

00:35 Substitute appropriate values according to the given data and solve

01:05 Calculate the square and products

01:17 One root is always equal to 1

01:27 These are the 2 possible solutions (addition,subtraction)

01:44 And this is the solution to the question

To solve the quadratic equation $x^2 - 3x + 2 = 0$ , we'll follow these steps:

Step 1: Check for factorization. Assuming the quadratic can be factored, we look for two numbers that multiply to $c = 2$ and add to $b = -3$ . These numbers are $-1$ and $-2$ .
Step 2: Factor the quadratic as $(x - 1)(x - 2) = 0$ .
Step 3: Solve each factor for $x$ .

Now, let's solve the factors:
From $(x - 1) = 0$ , we have $x = 1$ .
From $(x - 2) = 0$ , we have $x = 2$ .

Thus, the solutions to the equation are $x_1 = 1$ and $x_2 = 2$ .

Therefore, the solution to the problem is $x_1 = 1, x_2 = 2$ .

$x_1=1,x_2=2$