Solve the Quadratic Equation: x² - x - 20 = 0 Step-by-Step

Quadratic Formula with Integer Solutions

Solve the following equation:


x2x20=0 x^2-x-20=0

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find X
00:03 Use the roots formula
00:23 Identify the coefficients
00:39 Substitute appropriate values according to the given data and solve
00:54 Calculate the square and products
01:26 Calculate the square root of 81
01:33 These are the 2 possible solutions (addition,subtraction)
01:53 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following equation:


x2x20=0 x^2-x-20=0

2

Step-by-step solution

To solve the quadratic equation x2x20=0 x^2 - x - 20 = 0 using the quadratic formula, follow these steps:

  • Step 1: Identify the coefficients a a , b b , and c c in the equation. For our equation x2x20=0 x^2 - x - 20 = 0 , we have a=1 a = 1 , b=1 b = -1 , and c=20 c = -20 .
  • Step 2: Substitute these values into the quadratic formula: x=b±b24ac2a x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} .
  • Step 3: Calculate the discriminant Δ=b24ac\Delta = b^2 - 4ac:
    Δ=(1)241(20)=1+80=81 \Delta = (-1)^2 - 4 \cdot 1 \cdot (-20) = 1 + 80 = 81
  • Step 4: Since the discriminant is positive, there are two distinct real roots. Substitute back into the quadratic formula:
    x=(1)±8121=1±92 x = \frac{-(-1) \pm \sqrt{81}}{2 \cdot 1} = \frac{1 \pm 9}{2}
  • Step 5: Solve for the two possible values of x x :
    x1=1+92=5 x_1 = \frac{1 + 9}{2} = 5 x2=192=4 x_2 = \frac{1 - 9}{2} = -4

Therefore, the solutions to the equation x2x20=0 x^2 - x - 20 = 0 are x1=5 x_1 = 5 and x2=4 x_2 = -4 .

Accordingly, the correct choice matches with x1=4,x2=5 x_1 = -4, x_2 = 5 , which is option 3.

3

Final Answer

x1=4,x2=5 x_1=-4,x_2=5

Key Points to Remember

Essential concepts to master this topic
  • Standard Form: Identify coefficients a, b, c in ax² + bx + c = 0
  • Quadratic Formula: x = (-b ± √(b² - 4ac)) / 2a gives both solutions
  • Verification: Substitute x = -4: (-4)² - (-4) - 20 = 0 ✓

Common Mistakes

Avoid these frequent errors
  • Sign errors when substituting negative coefficients
    Don't substitute b = -1 as x = -(-1) without parentheses = wrong calculation! Students often write x = --1 instead of x = -(-1) = +1. Always use parentheses around negative values: x = (-(-1) ± √81) / 2.

Practice Quiz

Test your knowledge with interactive questions

a = Coefficient of x²

b = Coefficient of x

c = Coefficient of the independent number


what is the value of \( a \) in the equation

\( y=3x-10+5x^2 \)

FAQ

Everything you need to know about this question

Why are there two solutions to this quadratic equation?

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Quadratic equations create parabolas when graphed, and most parabolas cross the x-axis at two points. Each crossing point represents a solution where y = 0.

What does the discriminant tell me?

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The discriminant b24ac b^2 - 4ac tells you about solutions: positive = 2 real solutions, zero = 1 solution, negative = no real solutions. Here, 81 > 0, so we get 2 solutions!

Can I solve this by factoring instead?

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Absolutely! This factors as (x5)(x+4)=0 (x-5)(x+4) = 0 , giving x = 5 or x = -4. Factoring is often faster when it works easily!

How do I remember the quadratic formula?

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Try the song: "x equals negative b, plus or minus the square root, of b squared minus 4ac, all over 2a!" Practice writing it several times too.

What if I get a negative number under the square root?

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Then the equation has no real solutions! The parabola doesn't cross the x-axis. This happens when the discriminant b24ac b^2 - 4ac is negative.

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