Solve the Quadratic Equation: x²-4x+4=0 Step-by-Step

Question

Solve the following equation:

x24x+4=0 x^2-4x+4=0

Video Solution

Solution Steps

00:00 Find X
00:04 Identify the coefficients
00:19 Use the roots formula
00:43 Substitute appropriate values according to the given data and solve
01:07 Calculate the square and products
01:27 The square root of 0 equals 0
01:34 When the root equals 0, there is only one solution to the equation
01:50 And this is the solution to the question

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Recognize the given quadratic equation x24x+4=0 x^2 - 4x + 4 = 0 as a perfect square trinomial.
  • Step 2: Identify the factored form, which is (x2)2=0 (x - 2)^2 = 0 .
  • Step 3: Solve the factored equation to find the value of x x .

Now, let's work through each step:

Step 1: The problem gives us the quadratic equation x24x+4=0 x^2 - 4x + 4 = 0 . This equation is a perfect square trinomial because it can be rewritten as (x2)2=0 (x - 2)^2 = 0 .

Step 2: Recognize and rewrite the equation in its factored form:

(x2)2=0 (x - 2)^2 = 0 .

Step 3: To solve this factored equation, set the factor equal to zero:

x2=0 x - 2 = 0 .

Solving for x x , we get:

x=2 x = 2 .

In this case, the equation has a double root, x=2 x = 2 .

Therefore, the solution to the problem is x=2 x = 2 .

Answer

x=2 x=2