Solve the following problem:
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Solve the following problem:
Shown below is the given equation:
First note that on the left side we are able to factor the expression using a common factor. The largest common factor for the numbers and letters in this case is and this is due to the fact that the first power is the lowest power in the equation. Therefore it is included both in the term with the second power and in the term with the first power. Any power higher than this is not included in the term with the first power, which is the lowest. Hence this is the term with the highest power that can be factored out as a common factor from all terms in the expression. Continue to factor the expression:
Proceed to the left side of the equation that we obtained in the last step. There is a multiplication of algebraic expressions and on the right side the number 0. Therefore given that the only way to obtain 0 from a multiplication is to multiply by 0, at least one of the expressions in the multiplication on the left side must equal zero,
Meaning:
or:
Let's summarize then the solution to the equation:
Therefore the correct answer is answer B.
Solve the following equation:
\( 2x^2-8=x^2+4 \)
Factoring is much faster when you have a common factor! Since both terms contain x, factoring gives you in one step, while the quadratic formula requires more calculation.
The zero product property states: if two numbers multiply to give zero, at least one must be zero. So if , then either x = 0 or x-1 = 0.
A quadratic equation has at most 2 solutions. Since we found x = 0 and x = 1, and our equation is quadratic (highest power is 2), we have all solutions!
First move everything to one side: . This doesn't factor easily with integers, so you'd use the quadratic formula instead of factoring.
Absolutely! Zero is a perfectly valid solution. Many students think x = 0 "doesn't count," but it does! Always include zero when it satisfies the equation.
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