Solve the Quadratic Equation: x²+10x+25=0 Step-by-Step

Perfect Square Trinomials with Double Roots

Solve the following equation:

x2+10x+25=0 x^2+10x+25=0

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find X
00:04 Let's identify the coefficients
00:17 Let's use the roots formula
00:46 Let's substitute appropriate values according to the given data and solve
01:13 Let's calculate the square and products
01:24 The root of 0 is always equal to 0
01:29 When the root equals 0, there is only one solution to the equation
01:51 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following equation:

x2+10x+25=0 x^2+10x+25=0

2

Step-by-step solution

The given quadratic equation is x2+10x+25=0 x^2 + 10x + 25 = 0 .

Notice that x2+10x+25 x^2 + 10x + 25 is a perfect square trinomial, which can be factored as (x+5)2 (x + 5)^2 . Let's verify by expanding:

(x+5)2=(x+5)(x+5)=x2+5x+5x+25=x2+10x+25(x + 5)^2 = (x + 5)(x + 5) = x^2 + 5x + 5x + 25 = x^2 + 10x + 25.

Since the factoring is correct, we rewrite the equation:

(x+5)2=0(x + 5)^2 = 0 .

Take the square root of both sides:

x+5=0x + 5 = 0 .

Solving for x x , we find:

x=5x = -5.

The equation has a double root, meaning the solution is repeated. Thus, the final solution is:

x=5x = -5.

This matches the given correct answer.

3

Final Answer

x=5 x=-5

Key Points to Remember

Essential concepts to master this topic
  • Recognition: Perfect square trinomial follows pattern a2+2ab+b2 a^2 + 2ab + b^2
  • Technique: Factor as (x+5)2 (x + 5)^2 then solve x+5=0 x + 5 = 0
  • Check: Substitute x=5 x = -5 : (5)2+10(5)+25=0 (-5)^2 + 10(-5) + 25 = 0

Common Mistakes

Avoid these frequent errors
  • Using quadratic formula unnecessarily
    Don't automatically use the quadratic formula for x2+10x+25=0 x^2 + 10x + 25 = 0 = complex calculations with same result! This wastes time and increases error chances. Always check first if the trinomial is a perfect square that factors easily as (x+5)2 (x + 5)^2 .

Practice Quiz

Test your knowledge with interactive questions

a = Coefficient of x²

b = Coefficient of x

c = Coefficient of the independent number


what is the value of \( a \) in the equation

\( y=3x-10+5x^2 \)

FAQ

Everything you need to know about this question

How do I recognize a perfect square trinomial?

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Look for the pattern a2+2ab+b2 a^2 + 2ab + b^2 ! In x2+10x+25 x^2 + 10x + 25 , we have x² (first square), 25 (second square), and 10x (twice the product) since 2x5=10x 2 \cdot x \cdot 5 = 10x .

Why does this equation have only one solution?

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It's actually a double root! When (x+5)2=0 (x + 5)^2 = 0 , the factor (x+5) (x + 5) appears twice, giving us x=5 x = -5 with multiplicity 2.

Can I still use the quadratic formula?

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Yes, but it's unnecessarily complicated! You'd get x=10±1001002=10±02=5 x = \frac{-10 \pm \sqrt{100-100}}{2} = \frac{-10 \pm 0}{2} = -5 . Factoring is much faster!

What if I don't see the perfect square pattern?

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Practice recognizing common squares: 1, 4, 9, 16, 25, 36, 49... Then check if the middle term equals 2ab 2ab . For x2+10x+25 x^2 + 10x + 25 : does 10x=2(x)(5) 10x = 2(x)(5) ? Yes!

How do I verify my factoring is correct?

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Expand your factored form! (x+5)2=(x+5)(x+5)=x2+5x+5x+25=x2+10x+25 (x + 5)^2 = (x + 5)(x + 5) = x^2 + 5x + 5x + 25 = x^2 + 10x + 25

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