Solve the Quadratic Equation: x²-2x+8=0 Step-by-Step

Question

Solve the following equation:

x22x+8=0 x^2-2x+8=0

Video Solution

Solution Steps

00:00 Find X
00:04 Let's identify the coefficients
00:16 Let's use the roots formula
00:45 Let's substitute appropriate values according to the given data and solve
01:13 Let's calculate the square and products
01:24 A root cannot be a negative number
01:33 Therefore there is no solution to the question

Step-by-Step Solution

To solve the quadratic equation x22x+8=0 x^2 - 2x + 8 = 0 , we'll apply the quadratic formula method. The process is as follows:

  • Step 1: Identify the coefficients from the equation: a=1 a = 1 , b=2 b = -2 , c=8 c = 8 .
  • Step 2: Calculate the discriminant using the formula Δ=b24ac \Delta = b^2 - 4ac .
  • Step 3: For the given equation, calculate Δ=(2)24(1)(8)=432=28 \Delta = (-2)^2 - 4(1)(8) = 4 - 32 = -28 .
  • Step 4: Interpret the discriminant. Since Δ=28 \Delta = -28 is negative, this indicates there are no real solutions to the equation.

Without real roots, the equation has complex solutions. Since the problem requires real solutions, we conclude:

The equation x22x+8=0 x^2 - 2x + 8 = 0 has no real solution.

Answer

No solution