Solve the Quadratic Equation: x²-2x+8=0 Step-by-Step

Question

Solve the following equation:

x22x+8=0 x^2-2x+8=0

Video Solution

Solution Steps

00:05 Let's find the value of X.
00:09 First, let's identify the coefficients. Pay attention to the numbers in front of the variables.
00:21 Next, we'll use the roots formula. This helps us find solutions to the equation.
00:50 Now, substitute the correct values based on the data we have, and let's solve the equation.
01:18 Let's calculate the square and the products step by step.
01:29 Remember! A root cannot be negative. Keep this in mind.
01:38 So, there's no solution to this question. Great try, and keep practicing!

Step-by-Step Solution

To solve the quadratic equation x22x+8=0 x^2 - 2x + 8 = 0 , we'll apply the quadratic formula method. The process is as follows:

  • Step 1: Identify the coefficients from the equation: a=1 a = 1 , b=2 b = -2 , c=8 c = 8 .
  • Step 2: Calculate the discriminant using the formula Δ=b24ac \Delta = b^2 - 4ac .
  • Step 3: For the given equation, calculate Δ=(2)24(1)(8)=432=28 \Delta = (-2)^2 - 4(1)(8) = 4 - 32 = -28 .
  • Step 4: Interpret the discriminant. Since Δ=28 \Delta = -28 is negative, this indicates there are no real solutions to the equation.

Without real roots, the equation has complex solutions. Since the problem requires real solutions, we conclude:

The equation x22x+8=0 x^2 - 2x + 8 = 0 has no real solution.

Answer

No solution