Solve the following equation:
4x2+2x+41=0
To solve the equation 4x2+2x+41=0, we will follow these steps:
- Convert the equation to standard quadratic form.
- Identify the coefficients a, b, and c.
- Apply the quadratic formula.
- Calculate the discriminant and solve for x.
Step 1: The given equation is:
4x2+2x+41=0.
To convert it into standard form ax2+bx+c=0, multiply the entire equation by 4 to eliminate the denominators:
x2+2x+1=0.
Step 2: Identify the coefficients:
- a=1
- b=2
- c=1
Step 3: Apply the quadratic formula x=2a−b±b2−4ac.
Step 4: Calculate the discriminant b2−4ac:
b2−4ac=(2)2−4(1)(1)=4−4=0.
Since the discriminant is 0, we have one real repeated solution.
Step 5: Solve for x:
x=2(1)−2±0=2−2=−1.
Therefore, the solution to the equation is x=−1.