Solve the Quadratic Function Inequality: When is y = -0.9x² Less Than Zero?

Question

Given the function:

y=0.9x2 y=-0.9x^2

Determine for which values of x the following holds:

f\left(x\right) < 0

Step-by-Step Solution

To solve this problem, we need to determine when the quadratic function y=0.9x2 y = -0.9x^2 is less than zero. This requires analyzing the entire set of x-values.

  • Given that the function y=0.9x2 y = -0.9x^2 is a parabola opening downward because a=0.9<0 a = -0.9 < 0 , the function will take negative values for all x x except when x2=0 x^2 = 0 .
  • The vertex of this parabola is at the origin, x=0 x = 0 , since terms for linear (bx bx ) and constant (c c ) are zero in this function.
  • At x=0 x = 0 , y=0.9(0)2=0 y = -0.9(0)^2 = 0 , meaning at x=0 x = 0 , the function is exactly zero.
  • For any x0 x \neq 0 , the term x2>0 x^2 > 0 , hence 0.9x2<0 -0.9x^2 < 0 , indicating the function is negative.

Therefore, the function y=0.9x2 y = -0.9x^2 is less than zero for all values except at x=0 x = 0 .

Consequently, the solution to the problem is that the function is negative for all x0 x \ne 0 .

This corresponds to choice: x0 x\ne0 .

Answer

x0 x\ne0