Solve y=x²: Finding Values Where Function is Negative

Question

Given the function:

y=x2 y=x^2

Determine for which values of x f(x) < 0 holds

Step-by-Step Solution

To determine for which values of x x the function y=x2 y = x^2 satisfies f(x)<0 f(x) < 0 , we need to analyze the nature of the quadratic function.

Step 1: Recognize the function y=x2 y = x^2 is parabolic and opens upwards. For any real number x x , x2 x^2 is always non-negative, i.e., x20 x^2 \geq 0 .

Step 2: Since squaring any real number results in a value greater than or equal to zero, it is not possible for x2 x^2 to be less than zero.

Conclusion: Therefore, there are no real values of x x for which x2<0 x^2 < 0 . The correct conclusion is that no x x satisfies x2<0 x^2 < 0 .

Answer

x0 x\ne0