Solve the System: Equalizing |x+2| and |x-2| with x⁴ = 0

Systems of Equations with Polynomial Constraints

{x+2=x2x4=0 \begin{cases} |x+2|=|x-2| \\ x^4=0 \end{cases}

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1

Understand the problem

{x+2=x2x4=0 \begin{cases} |x+2|=|x-2| \\ x^4=0 \end{cases}

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Solve the polynomial equation x4=0 x^4 = 0 .
  • Step 2: Verify the solution against the absolute value equation x+2=x2 |x+2| = |x-2| .
  • Step 3: Ensure the solution matches a provided choice, if necessary.

Now, let's work through each step:

Step 1: Solving x4=0 x^4 = 0 yields x=0 x = 0 , as any non-zero values to the power of 4 would not equal zero.

Step 2: Substituting x=0 x = 0 into the absolute value equation:

0+2=02 |0+2| = |0-2|

2=2 |2| = |-2|

2=2 2 = 2 , thus the condition is satisfied.

Step 3: Compare with provided answer choices. Since the correct choice must satisfy both equations, x=0 x = 0 is consistent with option (1).

Therefore, the solution to the problem is x=0 x = 0 .

3

Final Answer

x=0 x=0

Key Points to Remember

Essential concepts to master this topic
  • Polynomial Rule: Solve x4=0 x^4 = 0 first to get x=0 x = 0
  • Verification Method: Substitute x=0 x = 0 into 0+2=02 |0+2| = |0-2| gives 2=2 2 = 2
  • System Check: Solution must satisfy both equations simultaneously for validity ✓

Common Mistakes

Avoid these frequent errors
  • Solving the absolute value equation first and ignoring the polynomial constraint
    Don't solve x+2=x2 |x+2| = |x-2| to get x=0 x = 0 and stop there = incomplete solution! The polynomial equation x4=0 x^4 = 0 is actually more restrictive and should be solved first. Always identify which equation provides the strongest constraint and solve that one first.

Practice Quiz

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\( \left|-x\right|=10 \)

FAQ

Everything you need to know about this question

Why should I solve the polynomial equation first?

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The equation x4=0 x^4 = 0 has only one solution (x=0 x = 0 ), while x+2=x2 |x+2| = |x-2| could have multiple solutions. Starting with the most restrictive equation saves time!

How do I solve absolute value equations like |x+2| = |x-2|?

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Absolute value equations A=B |A| = |B| mean either A = B or A = -B. So x+2=x2 x+2 = x-2 (impossible) or x+2=(x2) x+2 = -(x-2) which gives x=0 x = 0 .

What if the polynomial equation had no real solutions?

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If x4=0 x^4 = 0 had no solutions, then the entire system would have no solutions! In systems of equations, all equations must be satisfied simultaneously.

Can I check my answer by plugging into both equations?

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Absolutely! For x=0 x = 0 : Check 04=0 0^4 = 0 ✓ and 0+2=02 |0+2| = |0-2| gives 2=2 2 = 2 ✓ . Both work!

Why are the other answer choices wrong?

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Test them! For x=1 x = 1 : 14=10 1^4 = 1 ≠ 0 ✗. For x=2 x = 2 : 24=160 2^4 = 16 ≠ 0 ✗. Only x=0 x = 0 satisfies both equations.

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