Solve the following system of equations:
{3x−y=−109x−3y=−15
To solve this problem, let's apply the elimination method:
- Step 1: Write down the given equations:
3x−y=−10 and 9x−3y=−15.
- Step 2: Observe that the second equation is 3 times the first equation. Multiply the first equation by 3 for alignment:
3(3x−y)=3(−10) becomes 9x−3y=−30.
- Step 3: Compare the two resulting equations:
9x−3y=−30 and 9x−3y=−15.
- Step 4: Notice these equations suggest a contradiction as the left-hand side is the same (9x−3y), but the right-hand sides are different (−30 vs. −15).
As the comparison shows a contradiction, these lines are parallel and do not intersect.
Therefore, the system of equations has no solution.