Solve the following system of equations:
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Solve the following system of equations:
Note that in the current system of equations, one of the variables is isolated alone on the left side of the equation:
Therefore, we can apply the substitution method and substitute the entire expression that x equals in the second equation in place of x in the first equation (marked with an underline in both equations above) Hence we obtain one equation with one variable:
Highlight the equation in which the variable we substituted is isolated in order to return to it later.
From here - we'll proceed to solve the single-variable equation that we obtained.
First- combine like terms on the left side of the resulting equation:
Note that y cancelled out in the current equation and we obtained a false statement, as shown below:
meaning-
We obtained a false statement regardless of the variables' values,
We can conclude from here that the system of equations has no solution, given that no matter which values we substitute for the variables - we won't obtain a true statement in both equations together.
Therefore the correct answer is answer D.
There is no solution.
\( \begin{cases} x+y=8 \\ x-y=6 \end{cases} \)
This is a false statement that tells you the system has no solution! It means the two equations contradict each other and can never both be true at the same time.
When you substitute into , you get . The +y and -y cancel each other, leaving only constants.
No solution: Variables cancel and you get a false statement (like 5 = 8)
Infinite solutions: Variables cancel and you get a true statement (like 8 = 8)
Yes! You'd get the same result. From , rewrite as . Then you have and , which is clearly impossible!
Write "No solution" or "The system is inconsistent". Don't try to give specific x and y values because none exist that satisfy both equations.
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