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To solve this problem, we'll follow these steps:
Let's work through each step:
Step 1: Write the numbers vertically:
Step 2: Start with the ones place: Subtract 9 from 7. Since 7 is less than 9, we will borrow 1 from the tens column, making 7 become 17 in the ones place and reducing the 4 in the tens place to 3:
- Subtract 17 - 9 = 8
Step 3: Now, move to the tens place. Since we borrowed 1, adjust the tens place. Subtract 2 from 3:
- Subtract 3 - 2 = 1
So, writing the subtraction in full gives us:
Therefore, the solution to the problem is 18.
18
\( \begin{aligned} &105 \\ -& \\ &~~~~3 \\ &\underline{\phantom{776}} & \\ \end{aligned} \)
You cannot subtract a larger number from a smaller one in basic arithmetic! When the top digit is smaller, you must borrow from the next column to make subtraction possible.
Borrowing means taking 1 from the next column (worth 10 in the current column). So 7 becomes 17, and the tens digit decreases by 1. It's like trading a 1 bills!
Think of it as a two-step process: First, cross out the tens digit and write the new smaller number above it. Second, add 10 to the ones digit. This visual reminder helps you not forget!
When borrowing from 0, you need to borrow from the next column first. The 0 becomes 10, then you borrow 1 from that to get 9, and continue the borrowing process.
Use addition to check subtraction! Add your answer to the number you subtracted. If you get the original number (47), your subtraction is correct: 18 + 29 = 47 ✓
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