Solve Vertical Subtraction: 53 minus 36

$\begin{aligned} &53 \\ -& \\ &36\\ &\underline{\phantom{776}} & \\ \end{aligned}$

To solve this problem, we'll follow these steps:

• Step 1: Align the numbers by their place values, so the digits in the same position are directly on top of each other.

• Step 2: Subtract the digits in the ones place and perform borrowing if necessary.

• Step 3: Subtract the digits in the tens place after performing any borrowing from the previous step.

Now, let's work through each step:

Step 1: Align the numbers vertically:

$\begin{aligned} & 53 \\ - & 36 \\ \end{aligned}$

Step 2: Starting with the ones place, we see that 3 (in the minuend) is less than 6 (in the subtrahend). So we need to borrow.

• Borrow 1 from the tens place of 53, giving the tens place a value of 4. The borrowed number converts the ones place's 3 into 13.

Now subtract: $13 - 6 = 7$.

The new arrangement looks like this:

$\begin{aligned} \cancel{5}&4 ~~13 \\ -~~~&3~~~~6 \\ \overline{\phantom{123}}& \overline{\phantom{12345}} \\ \end{aligned}$

Step 3: Move to the tens place. After borrowing, the new value is 4.

Subtract: $4 - 3 = 1$.

Thus, the final result is:

$\begin{aligned} & 53 \\ - & 36 \\ & \underline{17} \\ \end{aligned}$

Therefore, the result of the subtraction $53 - 36$ is $\boxed{17}$.