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To solve this subtraction problem, we'll use the following steps:
Step 1: Subtract the ones place.
Step 2: Employ borrowing if necessary.
Step 3: Subtract the tens place after borrowing.
Now, let's apply these steps:
Step 1: Subtract the ones place.
In the ones place, we have . Since is smaller than , we need to borrow.
Step 2: Borrow from the tens place.
Borrow from the tens place, turning the into tens and in the ones place. Now, perform .
Step 3: Subtract the tens place after borrowing.
Now that we've borrowed, we have in the tens place. Subtract (there's nothing to subtract, effectively). So, the tens remain .
The final result after the subtraction is:
Therefore, the answer is .
58
\( \begin{aligned} &15 \\ -& \\ &~~4 \\ &\underline{\phantom{776}} & \\ \end{aligned} \)
Great question! Subtraction order matters! We must subtract bottom from top, not the other way around. When the top digit is smaller, we need to borrow to make it bigger first.
You need to borrow whenever the top digit is smaller than the bottom digit in any column. In this problem, 7 < 9, so we must borrow from the tens place.
When you borrow 1 ten, it becomes 10 ones. So 67 becomes 5 tens and 17 ones. The tens place goes from 6 to 5, and the ones place goes from 7 to 17.
Use addition to check! Add your answer to the number you subtracted: . If you get the original number, you're right!
When borrowing from 0, you need to keep borrowing from the next place over until you find a non-zero digit. It's like a chain reaction of borrowing!
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