Subtract 8 from 72: Vertical Format Arithmetic Problem

Question

amp;72amp;amp;  8amp;776amp; \begin{aligned} &72 \\ -& \\ &~~8 \\ &\underline{\phantom{776}} & \\ \end{aligned}

Video Solution

Solution Steps

00:03 Let's solve this problem.
00:06 We'll focus on each pair of digits.
00:09 Notice that 2 is smaller than 8.
00:13 So, we need to borrow 10 from the tens place.
00:18 Now, instead of 2, we have 12.
00:22 Subtract the bottom 8 from 12, and place the result in the ones.
00:28 The answer goes in the ones place.
00:31 Place 0 as a placeholder.
00:34 Finally, subtract the tens digits and write the answer there.
00:39 And that's how we solve it.

Step-by-Step Solution

To solve this vertical subtraction problem, follow these steps:

Step 1: Set up the problem vertically.

Write 72 and 8 ensuring that the digits are aligned according to their place values:

72
- 8
72\underline{\phantom{72}}

Step 2: Start subtracting from the rightmost digit (ones place).

In the ones place, we have 2 (from 72) and 8 (from -8). Since 2 is less than 8, we need to regroup.

Step 3: Perform regrouping.

Take 1 ten from the tens place of 72, leaving 6 tens. Adding 10 ones to 2 makes it 12 in the ones place.

Rewritten, the problem now looks like this:

6 12
- 8
72\underline{\phantom{72}}

Step 4: Continue with subtraction in the ones place.

Subtract 8 from 12, which equals 4.

Step 5: Subtract in the tens place.

Now, move to the tens place. We have 6 tens (from the regrouped value) and since there is no tens digit to subtract, it remains 6.

Conclusion: Combine the results from each place value to find the final difference: 66 tens and 44 ones make 6464.

Therefore, the solution to the problem is 64 64 .

Answer

64