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To solve this subtraction problem, we'll use the vertical subtraction method:
Step 1: Arrange the numbers in a column, aligning them by place value. The number 76 is our minuend, and 8 is our subtrahend.
Step 2: We start the subtraction from the rightmost column, the units place.
Step 3: Subtract 8 from 6 in the units column. Since 8 is greater than 6, we need to borrow from the tens column.
Let's break down the subtraction:
Since 8 cannot be subtracted directly from 6, we borrow 10 from the tens place.
This makes the 6 into 16 (i.e., ), and the 7 in the tens place becomes 6.
Now subtract in the units column:
Next, move to the tens column. After borrowing to help the units column:
remains as it is. There is nothing to subtract in the tens column (conceptually subtracting zero), so stays as .
As a result, the difference is:
Therefore, the solution to the subtraction is .
68
\( \begin{aligned} &15 \\ -& \\ &~~4 \\ &\underline{\phantom{776}} & \\ \end{aligned} \)
Because in subtraction, you must subtract the bottom number from the top number, not the other way around. When the top digit is smaller, you need to borrow from the left column first.
When you borrow 10 from the 7, it becomes 6. Think of it as trading one ten for ten ones. The 7 tens becomes 6 tens, and you add those 10 ones to the 6 in the units place.
You need to borrow whenever the top digit is smaller than the bottom digit in any column. In this problem, 6 is smaller than 8, so borrowing is necessary.
Yes! You can think logically: should be close to , but 2 more. So makes sense!
When there's no digit to subtract in the tens column (like here), you simply bring down the remaining digit after borrowing. The 6 stays as 6 in our final answer.
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