We have hundreds of course questions with personalized recommendations + Account 100% premium
To solve this problem, we'll follow these steps:
Step 1: Write the numbers vertically, with each digit aligned in their respective place value.
Step 2: Begin subtracting starting from the rightmost column.
Step 3: Move to the left, repeating the process for each subsequent column until finished.
Now, let's work through each step:
Step 1: Arrange the numbers vertically, aligning according to the decimal place. 39 Step 2: Start subtracting from the right. Subtract the ones place: .
- 6
----- 39 Step 3: Since there is no need to borrow, move to the tens place:
- 6
-----
3
The tens place comprises '3' from '39', as there is no corresponding digit above '6' to subtract from: . 39
- 6
-----
33
Therefore, the solution to the problem is .
33
\( \begin{aligned} &105 \\ -& \\ &~~~~3 \\ &\underline{\phantom{776}} & \\ \end{aligned} \)
We start from the ones place (rightmost) because that's how our number system works! Just like when you count, you go ones, tens, hundreds from right to left.
When there's no digit above (like no tens digit above the 6), treat it as zero. So 3 - 0 = 3 in the tens place.
Make sure the rightmost digits are directly above and below each other. The ones place should always line up first, then tens, then hundreds.
In this problem, we subtract 6 from 39, not the other way around. Always subtract the bottom number from the top number in vertical subtraction.
Add your answer to the number you subtracted: . If you get the original number (39), you're correct!
Get unlimited access to all 18 Arithmetic Operations questions, detailed video solutions, and personalized progress tracking.
Unlimited Video Solutions
Step-by-step explanations for every problem
Progress Analytics
Track your mastery across all topics
Ad-Free Learning
Focus on math without distractions
No credit card required • Cancel anytime