Solve (x-4)² = (x+2)(x-1): Perfect Square Equals Product

Quadratic Equations with Binomial Expansion

(x4)2=(x+2)(x1) (x-4)^2=(x+2)(x-1)

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find X
00:04 We'll use shortened multiplication formulas to open the brackets
00:08 Open brackets properly, multiply each factor by each term
00:33 Simplify what we can
00:42 Isolate X
00:57 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

(x4)2=(x+2)(x1) (x-4)^2=(x+2)(x-1)

2

Step-by-step solution

To solve the equation (x4)2=(x+2)(x1)(x-4)^2 = (x+2)(x-1), follow these detailed steps:

  • Step 1: Expand the left side of the equation using the square of a binomial formula: (x4)2=x28x+16(x-4)^2 = x^2 - 8x + 16.
  • Step 2: Expand the right side using the distributive property: (x+2)(x1)=x(x1)+2(x1)=x2x+2x2=x2+x2(x+2)(x-1) = x(x-1) + 2(x-1) = x^2 - x + 2x - 2 = x^2 + x - 2.
  • Step 3: Set the expanded forms equal to each other: x28x+16=x2+x2x^2 - 8x + 16 = x^2 + x - 2.
  • Step 4: Subtract x2x^2 from both sides to simplify: 8x+16=x2-8x + 16 = x - 2.
  • Step 5: Move all terms involving xx to one side and constant terms to the other: 8xx=216-8x - x = -2 - 16.
  • Step 6: Combine like terms: 9x=18-9x = -18.
  • Step 7: Solve for xx by dividing both sides by 9-9: x=2x = 2.

Therefore, the solution to the problem is x=2x = 2.

3

Final Answer

x=2 x=2

Key Points to Remember

Essential concepts to master this topic
  • Expansion: Use (ab)2=a22ab+b2 (a-b)^2 = a^2 - 2ab + b^2 for perfect squares
  • Technique: (x4)2=x28x+16 (x-4)^2 = x^2 - 8x + 16 and (x+2)(x1)=x2+x2 (x+2)(x-1) = x^2 + x - 2
  • Check: Substitute x = 2: (24)2=4 (2-4)^2 = 4 and (2+2)(21)=4 (2+2)(2-1) = 4

Common Mistakes

Avoid these frequent errors
  • Forgetting the middle term when expanding perfect squares
    Don't expand (x4)2 (x-4)^2 as just x2+16 x^2 + 16 = missing the -8x term! This loses crucial information and leads to completely wrong answers. Always include the middle term: (x4)2=x28x+16 (x-4)^2 = x^2 - 8x + 16 .

Practice Quiz

Test your knowledge with interactive questions

\( (3+20)\times(12+4)= \)

FAQ

Everything you need to know about this question

Why can't I just take the square root of both sides?

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You can't take the square root directly because the right side isn't a perfect square. (x+2)(x1) (x+2)(x-1) doesn't simplify to something squared, so you must expand both sides first.

How do I remember the perfect square formula?

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Think "First squared, minus twice the product, plus last squared": (ab)2=a22ab+b2 (a-b)^2 = a^2 - 2ab + b^2 . For (x4)2 (x-4)^2 : x22(x)(4)+42=x28x+16 x^2 - 2(x)(4) + 4^2 = x^2 - 8x + 16 .

What if the x² terms don't cancel out?

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If x2 x^2 terms don't cancel, you'll have a quadratic equation instead of linear. You'd need to use factoring, completing the square, or the quadratic formula to solve it.

How do I expand (x+2)(x-1) without making mistakes?

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Use FOIL: First + Outer + Inner + Last. (x+2)(x1)=xx+x(1)+2x+2(1)=x2x+2x2=x2+x2 (x+2)(x-1) = x \cdot x + x \cdot (-1) + 2 \cdot x + 2 \cdot (-1) = x^2 - x + 2x - 2 = x^2 + x - 2 .

Why do we get a linear equation from two quadratic expressions?

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After expanding both sides, the x2 x^2 terms are identical (x2 x^2 on both sides), so they cancel out when we subtract. This leaves us with a simpler linear equation to solve!

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