Solve (x-4)² + x(x-12) = 16: Finding Parameter x

Question

Find the value of the parameter x.

$(x-4)^2+x(x-12)=16$

00:00 Solve

00:04 Open parentheses according to the shortened multiplication formulas

00:08 Open parentheses properly, multiply by each factor

00:15 Calculate the multiplications and collect terms

00:23 Simplify what's possible

00:34 Factor out common terms

00:43 Find when each factor in the multiplication equals zero

00:47 This is one solution, find the second solution using the same method

00:54 And this is the solution to the problem

Let's open the parentheses, remembering that there might be more than one solution for the value of X:

$(x-4)^2+x(x-12)=16$

$x^2-8x+16+x^2-12x=16$

$2x^2-20x=0$

$2x(x-10)=0$

Therefore:

$x-10=0$

$x=10$

Or:

$2x=0$

$x=0$

$x=0,x=10$