Solve (X+4)(3+X) Given X=4: Binomial Multiplication Problem

Binomial Multiplication with Variable Substitution

Solve the exercise below given that:X=4 X=4

(X+4)(3+X) (X+4)(3+X)

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:09 Let's tackle this math problem together!
00:13 First, we'll substitute X with 4, based on the given data. Let's solve it step by step.
00:27 Next, calculate each part inside the parentheses separately.
00:32 Remember, there's multiplication between these parentheses.
00:36 And there you have it, that's our solution! Great job!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the exercise below given that:X=4 X=4

(X+4)(3+X) (X+4)(3+X)

2

Step-by-step solution

We start by substituting the value of X X

(4+4)(3+4) (4+4)(3+4)

First, we perform the calculation in parentheses

(8)(7) (8)(7)

After this, we solve the parentheses and can continue with the simple multiplication exercise.

7×8=56 7\times 8=56

3

Final Answer

56

Key Points to Remember

Essential concepts to master this topic
  • Substitution Rule: Replace variable with given value before any calculations
  • Technique: Simplify parentheses first: (4+4)(3+4) becomes (8)(7)
  • Check: Substitute X=4 into original: (4+4)(3+4) = 8×7 = 56 ✓

Common Mistakes

Avoid these frequent errors
  • Expanding binomials before substituting the variable
    Don't expand (X+4)(3+X) to X²+7X+12 then substitute = extra work and error risk! This makes the problem unnecessarily complex. Always substitute the given value first, then simplify the arithmetic.

Practice Quiz

Test your knowledge with interactive questions

Solve the following problem:

\( 187\times(8-5)= \)

FAQ

Everything you need to know about this question

Should I expand the binomials first or substitute X=4 first?

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Always substitute first! When you're given a specific value for the variable, replace it immediately. This turns algebra into simple arithmetic: (X+4)(3+X) (X+4)(3+X) becomes (8)(7)=56 (8)(7) = 56 .

What if I accidentally expanded the binomials first?

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No problem! If you get X2+7X+12 X^2 + 7X + 12 , just substitute X=4: 42+7(4)+12=16+28+12=56 4^2 + 7(4) + 12 = 16 + 28 + 12 = 56 . You'll get the same answer, but it's more work.

Why do I get the wrong answer when I don't use parentheses?

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Without parentheses, you might calculate 4+4×3+4 = 4+12+4 = 20 instead of (4+4)×(3+4) = 8×7 = 56. Always keep the grouping when substituting!

How can I check my answer is correct?

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Substitute X=4 back into the original expression and verify: (4+4)(3+4)=8×7=56 (4+4)(3+4) = 8×7 = 56 . If your calculation gives the same result, you're correct!

Does the order of multiplication matter?

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No! (8)(7) (8)(7) gives the same result as (7)(8) (7)(8) because multiplication is commutative. Both equal 56.

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