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Let's solve the given linear equation step-by-step:
Thus, the solution to the equation is .
Solve for x:
\( 2(4-x)=8 \)
When you have -6(3+y), the negative 6 multiplies everything inside the parentheses. So -6 × y = -6y, not +6y. Think of it as: -6(3+y) = (-6)(3) + (-6)(y) = -18 + (-6y).
Like terms have the same variable with the same power. In this problem, y and -6y are like terms (both have y¹), while -5 and -18 are like terms (both are constants with no variables).
Take it step by step! Write each operation clearly:
Substitute y = -6 into the original equation:
(-6-5) - 6(3+(-6)) = 7
(-11) - 6(-3) = 7
-11 + 18 = 7 ✓
Since 7 = 7, your answer is correct!
We have -5y - 23 = 7. To eliminate the -23, we need to do the opposite operation. The opposite of subtracting 23 is adding 23, so we add 23 to both sides to get -5y = 30.
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