Solve y = x² Function: Finding X When y = 16

What is the value of X for the function?

$y=x^2$

of the point $y=16$?

To solve this problem, let's find the steps required to determine $x$ when $y = 16$ in the function $y = x^2$:

• Step 1: Substitute the given $y$ into the equation to get $x^2 = 16$.
• Step 2: To solve $x^2 = 16$, take the square root of both sides, remembering to include both positive and negative roots. This yields $x = \pm\sqrt{16}$.
• Step 3: Simplify to find $x = \pm4$, which gives the solutions $x = 4$ and $x = -4$.

Thus, the value(s) of $x$ that satisfy $y = 16$ in the function $y = x^2$ are $x = 4$ and $x = -4$.

Therefore, the solution to the given problem is $x = 4, x = -4$.