Solve y=x² When y=25: Finding the X-Value

Quadratic Functions with Positive/Negative Solutions

What is the value of X for the function?

y=x2 y=x^2

of the point y=25 y=25 ?

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:06 First, let's set up the problem and find the solution.
00:10 Insert the given numbers where needed, and solve for the variable X.
00:17 Now, we'll extract the root of the number.
00:22 Remember, when extracting a root, there are two answers: one positive and one negative.
00:35 And that's how we find the solution to this question.

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

What is the value of X for the function?

y=x2 y=x^2

of the point y=25 y=25 ?

2

Step-by-step solution

Let's solve the problem by following these steps:

  • Step 1: Identify the equation to solve.
  • Step 2: Apply the square root to both sides of the equation.
  • Step 3: Solve for both positive and negative values of x x .

Step 1: We start with the equation derived from the function:
x2=25 x^2 = 25

Step 2: To isolate x x , we take the square root of both sides. Remember, the square root of a number can be both positive and negative:
x=±25 x = \pm \sqrt{25}

Step 3: Simplify the square root:
x=±5 x = \pm 5 , which means x=5 x = 5 or x=5 x = -5

Therefore, the values of x x that satisfy y=25 y = 25 in the function y=x2 y = x^2 are x=5 x = 5 and x=5 x = -5 .

Looking at the choices given, the correct answer is:

x=5,x=5 x=5,x=-5

3

Final Answer

x=5,x=5 x=5,x=-5

Key Points to Remember

Essential concepts to master this topic
  • Rule: Square root of both sides gives positive and negative solutions
  • Technique: x2=25 x^2 = 25 becomes x=±25=±5 x = ±\sqrt{25} = ±5
  • Check: Verify both values: 52=25 5^2 = 25 and (5)2=25 (-5)^2 = 25

Common Mistakes

Avoid these frequent errors
  • Forgetting the negative solution when taking square roots
    Don't just write x=25=5 x = \sqrt{25} = 5 and stop there = missing half the answer! The square of both positive and negative numbers gives positive results. Always include both x=+5 x = +5 and x=5 x = -5 when solving x2=25 x^2 = 25 .

Practice Quiz

Test your knowledge with interactive questions

Complete:

The missing value of the function point:

\( f(x)=x^2 \)

\( f(?)=16 \)

FAQ

Everything you need to know about this question

Why are there two answers for x when y = 25?

+

Because squaring eliminates the sign! Both 52 5^2 and (5)2 (-5)^2 equal 25. When you reverse the process by taking the square root, you must consider both possibilities.

How do I remember to include both positive and negative solutions?

+

Always write the ± symbol immediately when taking square roots: x=±25 x = ±\sqrt{25} . This reminds you that square roots have two values!

What does the graph of y = x² look like at y = 25?

+

The parabola y=x2 y = x^2 opens upward. At y=25 y = 25 , a horizontal line crosses the parabola at exactly two points: (5,25) (5, 25) and (5,25) (-5, 25) .

Can x² ever equal a negative number?

+

No! Squaring any real number (positive or negative) always gives a positive result. So x2=25 x^2 = -25 has no real solutions.

How do I check my answers?

+

Substitute each value back into the original equation. For our problem: 52=25 5^2 = 25 ✓ and (5)2=25 (-5)^2 = 25 ✓ . Both work!

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