Solve (y×7×3)⁴: Finding the Fourth Power of a Product

Exponent Rules with Multiple Variables

(y×7×3)4= (y\times7\times3)^4=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:09 Let's start by breaking it down.
00:12 We're using the power of products rule.
00:15 If a product is raised to a power, say N.
00:19 Each part of the product is raised to the same power N.
00:29 Now, let's apply this rule to solve our problem.
00:33 Open the parentheses. Raise each factor to the correct power.
00:38 And that's how we find the solution!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

(y×7×3)4= (y\times7\times3)^4=

2

Step-by-step solution

We use the power law for multiplication within parentheses:

(xy)n=xnyn (x\cdot y)^n=x^n\cdot y^n

We apply it in the problem:

(y73)4=y47434 (y\cdot7\cdot3)^4=y^4\cdot7^4\cdot3^4

Therefore, the correct answer is option a.

Note:

From the formula of the power property mentioned above, we can understand that it applies not only to two terms within parentheses, but also for multiple terms within parentheses.

3

Final Answer

y4×74×34 y^4\times7^4\times3^4

Key Points to Remember

Essential concepts to master this topic
  • Power Rule: Distribute exponents to each factor inside parentheses
  • Technique: Apply exponent 4 to y, 7, and 3 separately
  • Check: Count factors: (y73)4 (y\cdot7\cdot3)^4 has 12 total factors ✓

Common Mistakes

Avoid these frequent errors
  • Only applying the exponent to one factor
    Don't apply the exponent 4 to just one factor like y×7×34 y\times7\times3^4 = wrong distribution! This ignores the power rule and gives an incorrect result. Always distribute the exponent to every single factor inside the parentheses.

Practice Quiz

Test your knowledge with interactive questions

\( 112^0=\text{?} \)

FAQ

Everything you need to know about this question

Why does the exponent apply to all three factors?

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Because of the power rule: (abc)n=anbncn (abc)^n = a^n \cdot b^n \cdot c^n . When factors are multiplied inside parentheses, the exponent distributes to each one!

What if I have numbers and variables mixed together?

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It doesn't matter! The power rule works the same way. Both numbers (like 7 and 3) and variables (like y) get the exponent applied to them equally.

How do I calculate something like 7⁴?

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For 74 7^4 , multiply: 7×7×7×7=2401 7 \times 7 \times 7 \times 7 = 2401 . But in algebra problems, you can often leave it as 74 7^4 unless asked to simplify.

Does order matter when I write the final answer?

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No! y4×74×34 y^4 \times 7^4 \times 3^4 is the same as 74×34×y4 7^4 \times 3^4 \times y^4 . Multiplication is commutative, so you can write the factors in any order.

Can I simplify 7⁴ × 3⁴ further?

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Yes! Since both have the same exponent, you can write: 74×34=(7×3)4=214 7^4 \times 3^4 = (7 \times 3)^4 = 21^4 . So the final answer could also be y4×214 y^4 \times 21^4 .

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