The following is a series of structures formed by squares with side lengths of 1 cm.
In which structure (element) of the series are there 64 squares?
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The following is a series of structures formed by squares with side lengths of 1 cm.
In which structure (element) of the series are there 64 squares?
To solve this problem, follow these steps:
Now, let's work through each step:
Step 1: The sequence in question forms larger squares with each subsequent position based on the SVG graphic provided.
Step 2: We know that the nth position has n² squares: .
Step 3: Solving for n in the equation , we take the square root of both sides:
.
Therefore, the structure with 64 squares occurs at the 8th position in the series.
Thus, the correct answer is .
12 ☐ 10 ☐ 8 7 6 5 4 3 2 1
Which numbers are missing from the sequence so that the sequence has a term-to-term rule?
Look at the pattern! The first structure is 1×1 = 1 square, second is 2×2 = 4 squares, third is 3×3 = 9 squares. Each position n forms an n×n grid.
Great question! If the number wasn't a perfect square (like 50), then no structure in this sequence would have exactly that many squares. Always check if gives a whole number.
Because we need to find which position number gives us 64 squares total. Since position n has n² squares, we solve by taking .
Use your multiplication facts! Since 8 × 8 = 64, you know that 8² = 64. You can also think: 8 rows × 8 columns = 64 small squares.
The 10th structure would be a 10×10 square containing small unit squares. Each structure gets bigger as a perfect square!
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