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To solve this problem, we'll follow these steps:
Step 1: Write the numbers vertically.
Step 2: Start subtraction from the rightmost digit.
Step 3: Borrow where necessary.
Now, let's work through each step:
Step 1: Set up the subtraction vertically:
Step 2: Subtract starting from the rightmost digit:
In the one's place, we have . Since is smaller than , we need to borrow. However, has no value to lend, so we need to also borrow from the hundreds place.
In the tens place, becomes (after borrowing from the hundreds), but now we have to borrow for the ones place operation, leaving us with in the tens place. Thus, the ones place calculation becomes .
In the tens place, we subtract from the adjusted (due to earlier borrowing). Thus, .
In the hundreds place, initially , now we have (after borrowing from the thousands, so it effectively becomes ). Thus, .
Finally, the thousands place remains as we have already borrowed away, and we have no number to subtract from it. So, it remains .
The complete subtraction sequence gives us:
Therefore, the solution to the problem is .
1538
\( \begin{aligned} &15 \\ -& \\ &~~4 \\ &\underline{\phantom{776}} & \\ \end{aligned} \)
You cannot subtract a larger number from a smaller one in standard arithmetic. When you see 7 - 9, you must borrow from the tens place to make it 17 - 9 = 8.
Since 0 has nothing to lend, you must borrow through the zero! First borrow 1 from hundreds (making it 9), then the tens place becomes 10, then you can borrow 1 from tens for the ones place.
Work step by step from right to left. Write down each borrowed number as you go: 2007 becomes 2,0,0,7 → 1,10,0,7 → 1,9,10,7 → 1,9,9,17.
Borrowing is the standard method for multi-digit subtraction! Once you practice the pattern, it becomes automatic. The key is understanding that borrowing maintains the same total value.
Use addition to check subtraction! Add your answer (1538) to what you subtracted (469). If you get the original number (2007), your subtraction is correct!
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