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To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: We write and in vertical alignment for subtraction.
Step 2: Begin from the units column: We need to subtract from , so borrowing is required.
Step 3: As there are zeros in both the units and the tens place, we must borrow from the hundreds place and subsequently from the thousands place.
Step 4: Change as follows for borrowing: The thousands digit gives 1 to the hundreds, transforming so it looks like at hundreds, zero at the thousands, from which the hundreds gives 1 to the tens, and similarly tens gives 1 to the units.
The number effectively becomes temporarily while processing subtraction:
- Now units column: .
- In the tens column: .
- In the hundreds column: .
- Thousands column: .
Therefore, the solution to the subtraction problem of is .
49
\( \begin{aligned} &15 \\ -& \\ &~~4 \\ &\underline{\phantom{776}} & \\ \end{aligned} \)
You cannot subtract a larger number from a smaller one in basic arithmetic! When you see 0-1, you must borrow from the next column to make it 10-1 = 9.
You need to borrow through all the zeros! Each zero becomes a 9 after lending 1 to the right, until you reach a non-zero digit that can actually lend.
Think of it as breaking a big bill! The 1000 becomes 0 hundreds, 9 tens, 9 ones, and 10 in the working column. So for subtraction.
Borrowing is the standard method and helps you understand place value! You could also think: 1000 - 951 = 1000 - 1000 + 49 = 49, but learning to borrow builds important skills.
Use addition to check! Add your answer to the number you subtracted: 49 + 951. If you get the original number (1000), your answer is right!
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