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To solve the problem of subtracting 68 from 827, we will perform vertical subtraction with regrouping (borrowing) where necessary.
First, let's write the numbers vertically aligned by place value:
Next, we'll perform subtraction starting from the rightmost digit (units place):
The units column: 7 (from 827) minus 8. Since 7 is less than 8, we need to borrow 1 from the tens column. After borrowing, the 7 becomes 17.
17 minus 8 equals 9. Write 9 directly under this column.
Now, move to the tens column:
Since we borrowed 1, the 2 (from 827) is now 1. Subtract 6 (from 68) from 11 (the borrowed number).
11 minus 6 equals 5. Write 5 directly under this column.
Finally, the hundreds column:
Since no numbers exist below the hundreds place in 68 and we only borrowed from the tens place, we subtract nothing from 8. So, 8 stays the same.
Write 8 directly under this column.
Putting it all together, the complete difference is:
Therefore, the solution to the problem is .
759
\( \begin{aligned} &105 \\ -& \\ &~~~~3 \\ &\underline{\phantom{776}} & \\ \end{aligned} \)
You need to borrow when the top digit is smaller than the bottom digit in any column. Like when you see 7 - 8, you can't subtract a bigger number from a smaller one!
When you borrow 1 from a digit, that digit gets reduced by 1. So if you borrow from 2, it becomes 1. If you borrow from 8, it becomes 7.
Always borrow from the column to the left (the next higher place value). Think of it as borrowing 10 ones from the tens place, or 10 tens from the hundreds place.
If you need to borrow from 0, you'll need to borrow from the next column first. Turn that 0 into 10, then you can borrow 1 from it, leaving 9.
Use addition to check! Add your answer to the number you subtracted. If you get the original number back, you're right: ✓
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