Subtract 68 from 827: Vertical Format Arithmetic Problem

Video Solution

Solution Steps

00:00 Solve

00:03 Each time consider a shortage of 2 digits, and then we'll place

00:07 7 is less than 8

00:13 Therefore we subtract 1 from the tens and add this amount to the ones

00:17 In other words, now instead of 7 we'll have 17

00:20 Subtract the ones from the ones plus ten

00:23 Place in ones

00:28 1 is less than 6

00:32 Therefore we subtract 1 from the hundreds and add this amount to the tens

00:37 In other words, now instead of 1 we'll have 11

00:41 Subtract the tens from the tens plus ten

00:44 Place in tens

00:48 Place 0 in the missing digits

00:51 Subtract hundreds from hundreds, and place in hundreds

00:55 And this is the solution to the question

Step-by-Step Solution

To solve the problem of subtracting 68 from 827, we will perform vertical subtraction with regrouping (borrowing) where necessary.

First, let's write the numbers vertically aligned by place value:

$\begin{aligned} &827 \\ -&\phantom{0}68 \\ &\underline{\phantom{776}} \\ \end{aligned}$

Next, we'll perform subtraction starting from the rightmost digit (units place):

The units column: 7 (from 827) minus 8. Since 7 is less than 8, we need to borrow 1 from the tens column. After borrowing, the 7 becomes 17.
17 minus 8 equals 9. Write 9 directly under this column.

Now, move to the tens column:

Since we borrowed 1, the 2 (from 827) is now 1. Subtract 6 (from 68) from 11 (the borrowed number).
11 minus 6 equals 5. Write 5 directly under this column.

Finally, the hundreds column:

Since no numbers exist below the hundreds place in 68 and we only borrowed from the tens place, we subtract nothing from 8. So, 8 stays the same.
Write 8 directly under this column.

Putting it all together, the complete difference is:

$\begin{aligned} &827 \\ -&\phantom{0}68 \\ &\overline{759} \\ \end{aligned}$

Therefore, the solution to the problem is $759$ .